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3 years ago

An elevator ascends at a constant speed of 4 m/s, how much time is required for the elevator in order to travel 120 m upwards?

Physics

2 answers:

bekas [8.4K]3 years ago

6 0

Hello, Reenation12

The correct and aprooved answer is 30 m/s

This answer is really easy to get all you need to do is shown below

120 divided by 4 equals 30

If my answer helped please rate me as brainliest leave a thanks and rate my answer 5 stars thank you and have theh best day ever!

Dominik [7]3 years ago

5 0

Divide 120 by 4, to get 30 seconds

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The best answer would be:

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3 years ago

The force involves the attraction between objects with mass. Strong nuclear. Gravitational. Electromagnetic. Weak nuclear

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The answer is Gravitational.

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3 years ago

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NISA [10]

The first step that Enrique must take in order to calculate the tangential speed of the satellite is to convert the period from days to seconds.

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3 years ago

A 23.5 g piece of aluminum metal is initially at 100.0°C. It is dropped into a coffee cup-calorimeter containing 130.0 g of wate

vivado [14]

Answer: The molar heat capacity of aluminum is $25.3J/mol^0C$

Explanation:

$heat_{absorbed}=heat_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ .................(1)

where,

q = heat absorbed or released

$m_1$ = mass of water = 130.0 g

$m_2$ = mass of aluminiunm = 23.5 g

$T_{final}$ = final temperature = $26.0^oC=(273+26)K=299K$

$T_1$ = temperature of water = $23^oC=(273+23)K=296K$

$T_2$ = temperature of aluminium = $100^oC=273+100=373K$

$c_1$ = specific heat of water= $4.184J/g^0C$

$c_2$ = specific heat of aluminium= ?

Now put all the given values in equation (1), we get

$130.0\times 4.184\times (299-296)=-[23.5\times c_2\times (299-373)]$

$c_2=0.938J/g^0C$

Molar mass of Aluminium = 27 g/mol

Thus molar heat capacity = $0.938J/g^0C\times 27g/mol=25.3J/mol^0C$

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3 years ago

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