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4 years ago

An elevator ascends at a constant speed of 4 m/s, how much time is required for the elevator in order to travel 120 m upwards?

Physics

2 answers:

bekas [8.4K]4 years ago

6 0

Hello, Reenation12

The correct and aprooved answer is 30 m/s

This answer is really easy to get all you need to do is shown below

120 divided by 4 equals 30

If my answer helped please rate me as brainliest leave a thanks and rate my answer 5 stars thank you and have theh best day ever!

Dominik [7]4 years ago

5 0

Divide 120 by 4, to get 30 seconds

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A thin uniform cylindrical turntable of radius 2.2 m and mass 35 kg rotates in a horizontal plane with an initial angular speed

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The given data is as follows.

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4 years ago

What is the magnitude of the net force needed to bring a 2110 kg car to rest from 18.1 m/s in 7.0 seconds?

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Here is what we know:
a = ?, s = ?, u = 18.1m/s, v = zero/rest, t = 7.0s, m = 2110kg

(a = acceleration, s= displacement, u = initial velocity, v = final velocity, t = time and m is mass)

Now we choose a kinematic formula. Since we know v, u and t, we will use the formula: v = u+at and rearrange it so that we can find a.
a = v-u/t
a = 0-18.1/7.0 = -2.5857...
therefore, a = -2.6m/s

We have our acceleration, now let’s find the net force. To find the force we use one of Newtons laws of motion.
We will use Newtons second law since it describes what happens when one or more forces act upon an object.
F = ma
F = (2110kg)(-2.6m/s)
F = -5486 kg
Therefore the net force F = -5486 N

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4 years ago