Answer:
The force is 
Explanation:
The moment of Inertia I is mathematically evaluated as
Substituting 
for M(Mass of the wheel) and 
for 
(Radius of wheel)
The torque on the wheel due to net force is mathematically represented as
Substituting 135 N for 
(Force acting on sprocket),
for 
(radius of the chain) and F is the force acting on the sprocket due to the chain which is unknown for now
This same torque due to the net force is the also the torque that is required to rotate the wheel to have an angular acceleration of 
and this torque can also be represented mathematically as
Now equating the two equation for torque
Making F the subject
Substituting values
Not having clean water to drink or bath. Also some organizations that live in the water might die because the water is polluted and that would be toxic form them
<span>Answer:
The moments of inertia are listed on p. 223, and a uniform cylinder through its center is:
I = 1/2mr2
so
I = 1/2(4.80 kg)(.0710 m)2 = 0.0120984 kgm2
Since there is a frictional torque of 1.20 Nm, we can use the angular equivalent of F = ma to find the angular deceleration:
t = Ia
-1.20 Nm = (0.0120984 kgm2)a
a = -99.19 rad/s/s
Now we have a kinematics question to solve:
wo = (10,000 Revolutions/Minute)(2p radians/revolution)(1 minute/60 sec) = 1047.2 rad/s
w = 0
a = -99.19 rad/s/s
Let's find the time first:
w = wo + at : wo = 1047.2 rad/s; w = 0 rad/s; a = -99.19 rad/s/s
t = 10.558 s = 10.6 s
And the displacement (Angular)
Now the formula I want to use is only in the formula packet in its linear form, but it works just as well in angular form
s = (u+v)t/2
Which is
q = (wo+w)t/2 : wo = 1047.2 rad/s; w = 0 rad/s; t = 10.558 s
q = (125.7 rad/s+418.9 rad/s)(3.5 s)/2 = 952.9 radians
But the problem wanted revolutions, so let's change the units:
q = (5528.075087 radians)(revolution/2p radians) = 880. revolutions</span>
