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Aleonysh [2.5K]
2 years ago
12

What is the most common kind of element in the solar wind?

Physics
1 answer:
eimsori [14]2 years ago
8 0
OzsnuhgnowgnwrfoqingoiwrgWWR  KEFQF QEFI FBI O8QE VU F8EINFOQIHWJ OU JN  K kjbJ IUJ j osd sfljvbwj 9 oirs jf bhfb wjsf jfow vj  isfobsfjb io jio ofsjb
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A 0.14 -kg baseball is moving at 41 m/s. A 0.058-kg tennis ball is moving at 67 m/s. Which of the two balls has higher kinetic e
Iteru [2.4K]
Since kinetic energy is a form of energy using the equation KE=¹/₂mv², the units of measurement is in Joules (J). Therefore, the tennis ball had more kinetic energy than the baseball since velocity is a larger factor than the mass is when determining kinetic energy.

3 0
3 years ago
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If something is being carried by westerlies, what direction is it moving??
sergejj [24]
Winds are immigrants. They're named for where they have already been and are coming from, not for where they're going.

A Westerly wind is coming from the West. Anything caught in it is being blown toward the east.
7 0
3 years ago
At some distance from a point charge, the electric potential is 635.0 V and the magnitude of the electric field is 189.0 N/C. Fi
Nataliya [291]

Answer:

The distance from the charge is 3.35 m.                

Explanation:

Given that,

Electric potential, V = 635 V

Magnitude of electric field, E = 189 N/C

We need to find the distance from the charge. We know that the relation between electric field and electric potential is given by :

E=\dfrac{V}{d}

d is the distance from charge

d=\dfrac{V}{E}\\\\d=\dfrac{635}{189}\\\\d=3.35\ m

So, the distance from the charge is 3.35 m. Hence, this is the required solution.

8 0
3 years ago
Who was the first known contributor to the atomic theory? Select one: a. Thomson b. Bohr c. Dalton d. Democritus
ser-zykov [4K]
It would be D Democritus
He contributed in around 460-370 BC
Whereas the others contributed much later from around 1700's - 1900's
6 0
3 years ago
Monochromatic light from a distant source is incident on a slit 0.705 mm wide. On a screen 2.13 m away, the distance from the ce
vampirchik [111]

Answer:

492.183 nm

Explanation:

x = Distance from the central maximum to the first minimum = 1.35 mm

l = Distance of screen = 2.13 m

d = Distance of gap = 0.705 mm

m = Order = 1

We have the relation

tan\theta=\dfrac{x}{l}\\\Rightarrow \theta=tan^{-1}\dfrac{1.35\times 10^{-3}}{2.13}\\\Rightarrow \theta=0.04^{\circ}

dsin\theta=m\lambda\\\Rightarrow \lambda=\dfrac{dsin\theta}{m}\\\Rightarrow \lambda=\dfrac{0.705\times 10^{-3}\times sin0.04}{1}\\\Rightarrow \lambda=4.92183\times 10^{-7}=492.183\ nm

The wavelength of the light is 492.185 nm

5 0
3 years ago
Read 2 more answers
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