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Irina-Kira [14]
3 years ago
11

A student discovers that sound waves travel 1,687.5 meters in 5 seconds through air at a temperature of 10°C. Based on this info

rmation, determine the speed of sound, in m/s, through air at this temperature.
Physics
1 answer:
vitfil [10]3 years ago
8 0

Answer:

The speed of sound, in m/s, through air at this temperature is 343.5 m/s

Explanation:

Given;

distance traveled by sound, d = 1,687.5 meters

time taken for the sound to travel, t = 5 seconds

air temperature, θ = 10°C

Speed of sound = distance traveled by sound / time taken for the sound to travel

Speed of sound = d / t

                           = 1687.5 m / 5 s

                           = 337.5 m/s

Speed of sound at the given temperature is calculated as;

c = 337.5 + 0.6θ

c = 337.5 + 0.6 x 10

c = 337.5 + 6

c = 343.5 m/s

Therefore, the speed of sound, in m/s, through air at this temperature is 343.5 m/s

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seraphim [82]

Answer:

51kg

Explanation:

w=FxS

2500=Fx5

F=2500/5=500

mass = 500/9.8 = 51kg

7 0
2 years ago
Calculate the average velocity of a motor cycle that travels 72km/hr in<br> 20 seconds
olchik [2.2K]
Velocity =displacement
Change in time
D=72km/hr
Time=20s
But the S.I unit of velocity is m/s so you woul have to change 72km/hr to m/s

Changing 72km to m

1 kilometer=1000meters
Then, 72 kilometers =?

72•1000/1
=72000m

Changing 72hours to seconds

If 1 hour = 3600 seconds
Then 72 hours=?

72•3600/1

=259200 seconds


Velocity =displacement
Change in time

V= 72,000
259,2005
=0.028m/s
3 0
3 years ago
A 4.0-kg object is supported by an aluminum wire of length 2.0 m and diameter 2.0 mm. How much will the wire stretch?
forsale [732]

Answer:

The extension of the wire is 0.362 mm.

Explanation:

Given;

mass of the object, m = 4.0 kg

length of the aluminum wire, L = 2.0 m

diameter of the wire, d = 2.0 mm

radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

A = π(0.001)² = 3.142 x 10⁻⁶ m²

The downward force of the object on the wire is given by;

F = mg

F = 4 x 9.8 = 39.2 N

The Young's modulus of aluminum is given by;

Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm

Therefore, the extension of the wire is 0.362 mm.

8 0
3 years ago
If the same types of fossils are found in two separate rock layers, it's likely that the two rock layers ____. A-formed at diffe
zmey [24]
<span>B-are part of one continuous deposit.</span>
5 0
3 years ago
Read 2 more answers
A 15-lb block B starts from rest and slides on the 25-lb wedge A, which is supported by a horizontal surface. Neglecting frictio
xxTIMURxx [149]

The angle of the wedge is 30°.

Answer:

5.88 ft/s

Explanation:

a) The block will slide down due to it's weight.

initial velocity u= 0

final velocity, v

acceleration, a = g sin 30° = 32 ft/s²× sin 30° = 16 ft/s²

Sliding displacement, s = 3ft

Use third equation of motion:

v^2-u^2 = 2as

substitute the values and solve for v

v^2-0 = 2\times 16 \times 3 =96 ft^2/s^2\\v = 9.8 ft/s

b) Use conservation of momentum:

Initial momentum of the system  = 0

final momentum = (15) ( 9.8)+ (25)(v')

v' = 5.88 ft/s

3 0
3 years ago
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