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3 years ago

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Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to A. be decreased by t

wo thirds. B. be increased by two thirds. C. be decreased by one third. D. be increased by one third

1 answer:

Nostrana [21]3 years ago

5 0

Reducing the volume of contained gas by one third, while holding temperature constant, causes pressure to D. be increased by one third

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If 20.0g of water at 56.2℃ absorbs 195 J of heat, what is the final temperature? *

Gnom [1K]

Answer

Explanation:

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3 years ago

The atomic number is determined only by the number of ________ in the nucleus of an atom. But, in a neutral atom it also represe

sveticcg [70]

Hello!

The atomic number is determined only by the number of protons in the nucleus of an atom. But, in a neutral atom it also represents the number of electrons in the electron cloud.

Neutrons are only important in the nucleus for helping us find atomic weight, which varies as we move along the perodic table and does not always equal the same amount of it's atomic number. Which is why it would not be a suitable answer for the first blank space. Electrons do not work either as they do not exist inside the nucleus but rather outside the atom.

The second space, since it states is in the electron cloud, we can deduct that electrons would be an appropriate answer there.

If you need anymore help feel free to ask, but I hope this answers your question.

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3 years ago

How many grams of Ni are formed from 55.3 g of Ni2O3?<br><br> 2Ni2O3(s)⟶4Ni(s)+3O2(g)

Neko [114]

Answer:

39.2 g

Explanation:

2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)

First we <u>convert 55.3 grams of Ni₂O₃ into moles of Ni₂O₃</u>, using its<em> molar mass</em>:

55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃

Then we <u>convert 0.334 moles of Ni₂O₃ into moles of Ni</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

0.334 mol Ni₂O₃ * $\frac{4molNi}{2molNi_2O_3}$ = 0.668 mol Ni

Finally we <u>calculate how much do 0.668 Ni moles weigh</u>, using the<em> molar mass of Ni </em>:

0.668 mol Ni * 58.69 g/mol = 39.2 g

7 0

3 years ago

HELP QUICK ASSESMENT

ehidna [41]

Answer:

MAGNESIUM

Explanation:

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2 years ago

Read 2 more answers

Calculate the wavelength, in nanometers, of the spectral line produced when an electron in a hydrogen atom undergoes the transit

Lapatulllka [165]

<u>Answer:</u> The wavelength of spectral line is 656 nm

<u>Explanation:</u>

To calculate the wavelength of light, we use Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_f^2}-\frac{1}{n_i^2} \right )$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $1.097\times 10^7m^{-1}$

$n_f$ = Final energy level = 2

$n_i$ = Initial energy level = 3

Putting the values in above equation, we get:

$\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.524\times 10^6m^{-1}}=6.56\times 10^{-7}m$

Converting this into nanometers, we use the conversion factor:

$1m=10^9nm$

So, $6.56\times 10^{-7}m\times (\frac{10^9nm}{1m})=656nm$

Hence, the wavelength of spectral line is 656 nm

6 0

3 years ago