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Reil [10]
3 years ago
13

Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to A. be decreased by t

wo thirds. B. be increased by two thirds. C. be decreased by one third. D. be increased by one third
Chemistry
1 answer:
Nostrana [21]3 years ago
5 0
Reducing the volume of contained gas by one third, while holding temperature constant, causes pressure to D. be increased by one third
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2NO (g) + O2 (g) →2NO2 (g) At equilibrium [NO] = 2.4 × 10 -3 M, [O2] = 1.4 × 10 -4 M, and [NO2] = 0.95 M.
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Answer:

K=1.12x10^9

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Hello there!

Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:

K=\frac{[NO_2]^2}{[NO]^2[O_2]}

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3 years ago
What is the mass of an osmium block that measures 6.70 cm × 9.20 cm × 3.30 cm? The density of osmium is given as 22.610 g/cm3. N
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m= 4,599.145 g

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a balanced chemical equation occurs when the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.

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