Initial velocity=10m/s=u
Final velocity=v=15m/s
Time=t=2s
____ occurs when waves spread out and travel around obstacles or through openings in obstacles.
1 answer:
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1. In the first 1.5 seconds, the lift accelerates from 0 to 3m/s. By definition, the acceleration is the ratio between the change in velocity and the time elapsed to change the velocity.
The change in velocity is .
The time elapsed is 1.5 seconds, so the acceleration is
meters per second squared.
2. We know, from the previous point, that the lift travelled 20m from the first floor. Since it returns to the first floor after the ascent, it must travel again those same 20m, just in reverse (descending instead of ascending). So, the total distance travelled is meters.
The displacement, though, is zero, because it measures the distance between the starting and ending point of a certain motion. Since the lift starts and ends its motion at the same place (the first floor), its total displacement is zero.
Answer:
Explanation:
Let's use the conservation of angular momentum here. If there is a conservation the addition of both must be zero.
The momentum of inertia of both are:
The angular momentum is the product between angular velocity and momentum of inertia.
Let's solve it for ω(t).
But
- R is the radius R=D/2 = 30 cm = 0.3 m
- V is the steady speed V = 0.74 m/s
Knowing that 2π rad is a rev. We have.
The minus sign means the track is moving opposite of the car.
I hope it helps you!
Answer:
The magnitude of the applied force is 94.74 N
Explanation:
Mass of the block, m = 11 kg
Angle of inclination of the plane,
Friction coefficient,
Now,
Normal force that acts on the block is given by:
(1)
Now, to maintain the equilibrium parallel to ramp the forces must be balanced.
Thus
(2)
From eqn (1) and (2)
F = 94.74 N