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umka2103 [35]
3 years ago
14

What happens when an electric charge passes through a circuit?

Physics
2 answers:
igomit [66]3 years ago
7 0

Answer:

the electric currents travel through and lead to the object it's flowing into

sleet_krkn [62]3 years ago
5 0

Answer:

The electric field direction within a circuit is by definition the direction that positive test charges are pushed. Thus, these negatively charged electrons move in the direction opposite the electric field.

Explanation:

: )

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The noble gases have eight valence electrons and as a result are
AURORKA [14]
The noble gases have eight valence electrons and as a result are stable. 

If an atom consists of 8 valence electrons, they have a full octet, and do not need to bond, which makes them "happy".
4 0
4 years ago
The charge on any negatively charged oil droplet is always a whole-number multiple of the fundamental charge of a single electro
shusha [124]

Answer:

1.6\times 10^{-18} C  

Explanation:

The fundamental charge of a single electron is 1.6\times 10^{-19} C.

If there are 10 excess electrons, the net charge that would be measured should be 10 times the fundamental charge of a single electron:

Q=nq_e\\Q= 10\times 1.6\times 10^{-19} C\\Q= 1.6 \times 10^{-18} C

3 0
3 years ago
1.A steel cable is attached to a ring on the top of a street light. The weight of the street light is W . The other end of the c
mixer [17]

Answer:

a) Please find attached, the vector diagram regarding the question

i) The direction of the sum of the vectors is the negative direction of the vertical or y-axis

ii) The scale is 1 mm = 1 N

W = 25 N

The mass of W is approximately 2.55 kg

Explanation:

The given parameters are;

The angle of inclination of the cable to the vertical = 55°

The tension in the cable = 43.6 N

a) i) The direction of the vector sum of the two forces is given as the resultant of the two forces;

The component of the tension in the chain is given as follows;

Tension in the horizontal chain = x\mathbf{ \hat i}

The resolved force in the cable is given as follows;

Given that the force is acting upwards along the cable

F = 43.6 × -sin(55°)\mathbf{ \hat i} + 43.6 × cos(55°)\mathbf{ \hat j}

F ≈ -35.72 \mathbf{ \hat i}+ 25 \mathbf{ \hat j}

Therefore, from ∑Fₓ = 0 and ∑F_y = 0, since the horizontal force in the chain will balance the horizontal component of the tension in the cable, there will be no net horizontal force and the resultant force will have a direction of the vertical y-axis

ii)

Given that ∑F = 0, we have;

The tension in the cable is an horizontal force, therefore, we have;

∑Fₓ = 0

The tension in the horizontal chain + The horizontal component of the cable = 0

The tension in the horizontal chain - 35.72 N = 0

∴ The tension in the horizontal chain = 35.72 N

The weight of the street light + The vertical component of the tension = 0

The weight of the street light  + 25 N = 0

Therefore;

The weight of the street light  W = -25 N

The scale of the vector diagram used is <u>1 mm = 1 N</u>

W = -25 N

The mass of the street light = Weight of the street light/(Acceleration due to gravity)

The mass of the street light = 25 N/(9.81 m/s²) ≈ 2.55 kg

7 0
3 years ago
An electric motor that transforms 1000 J of chemical potential energy into 975 J of kinetic energy and 25 J of wasted heat energ
Musya8 [376]

Answer:

97.5% I believe

Explanation:

My answer needs to be 20characters long so I'm typing this

8 0
3 years ago
What does this diagram show?
iren2701 [21]

Answer: One Primary Consumer! Hope this helps:)

Explanation:

7 0
3 years ago
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