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garik1379 [7]
2 years ago
5

a 1 kg ball is confined to move on a. vertical circle of a radius 2 meters. There is no friciton between the bead and the circul

ar track. The bead has a speed of 10 m/s when at the top of the circle at point A, adn the total
Physics
1 answer:
monitta2 years ago
3 0

The total centripetal force is 50N

Given

mass of the ball= 1kg

speed of the ball = 10m/s

Radius = 2m

we know that

centripetal force = F =\frac {mv^2}{r}

F = \frac {1 \times {10}^2}{2} = 50 N

<h3>What is Centripetal force?</h3>
  • A force that causes a body to follow a curved path is known as a centripetal force.
  • It always moves in a direction that is the opposite of the body's velocity and in the direction of the immediate center of curvature of the path. It is "a force by which bodies are dragged or driven, or in any other way gravitate, towards a point as to a center," according to Isaac Newton.
  • Gravity is the centripetal force that drives astronomical orbits according to Newtonian mechanics.

To learn more about centripetal force with the given link

brainly.com/question/11324711

#SPJ4

Question:

a 1 kg ball is confined to move on a. vertical circle of a radius of 2 meters. There is no friction between the bead and the circular track. The bead has a speed of 10 m/s when at the top of the circle at point A, find the total centripetal force.

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Glycerin at a temperature of 30 degrees celcius flows at a rate of 8×10−6m3/sthrougha horizontal tube with a 30mmdiameter. what
marusya05 [52]

The pressure drop in pascal is 3.824*10^4 Pascals.

To find the answer, we need to know about the Poiseuille's formula.

<h3>How to find the pressure drop in pascal?</h3>
  • We have the Poiseuille's formula,

                     Q=\frac{\pi r^4P}{8\beta l}

  • where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.
  • By substituting values and rearranging we will get the pressure drop as,

                  P=3.284Pascals

Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4.

Learn more about the Poiseuille's formula here:

brainly.com/question/13180459

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3 0
1 year ago
When two waves collide and create a taller wave, what interference occurs?
oksano4ka [1.4K]

It would be Constructive interference. It occurs when two waves collide and make a taller wave. 
3 0
3 years ago
Carbon is allowed to diffuse through a steel plate 9.7-mm thick. The concentrations of carbon at the two faces are 0.664 and 0.3
cupoosta [38]

Answer:

844°C

Explanation:

The problem can be easily solve by using Fick's law and the Diffusivity or diffusion coefficient.

We know that Fick's law is given by,

J = - D \frac{\Delta c}{\Delta x}

Where \frac{\Delta c}{\Delta x} is the concentration of gradient

D is the diffusivity coefficient

and J is the flux of atoms.

In the other hand we have, that

D= D_0 e^{\frac{E_d}{RT}}

Where D_0 is the proportionality constant,

R is the gas constant, T the temperature and E_d is the activation energy.

Replacing the value of diffusivity coefficient in Fick's law we have,

J = -D_0 ^{\frac{E_d}{RT}}\frac{\Delta c}{\Delta x}

Rearrange the equation to get the value of temperature,

T=\frac{Ed}{Rln(\frac{J\Delta x}{D_0 \Delta c})}

We have all the values in our equation.

\Delta c = 0.664-0.339 = 0.325 C. cm^{-1}

\Delta x = 9.7*10^{-3}m

E_d = 82000J

D_0 = 6.5*10^{-7}m^2/s

J = 3.2*10^{-9}m^2/s

R= 8.31Jmol^{-1}K

Substituting,

T=\frac{Ed}{Rln(\frac{J\Delta x}{D_0 \Delta c})}

T=-\frac{-82000}{(8.31)ln(\frac{3.2*10^{-9}(9.7*10^{-3})}{6.5*10^{-7} (0.325)})}

T=1118.07K=844\°C

4 0
3 years ago
How can humidity be used to predict if it is going to rain?
postnew [5]
1. Humidity cannot be used to predict rain.
2. I'm pretty sure it's weather but I'm not 100% sure. Maybe like 89% sure.

3. Tempurature doesn't affect humidity.

4. Not sure but I think its the 3rd one
3 0
3 years ago
6. One minute after takeoff, a rocket carrying the space shuttle into outer space reaches a speed of 447 m/s.
Sidana [21]

Answer:

acceleration of the rocket is given as

a = 7.45 m/s^2

Explanation:

As we know that rocket starts from rest and then reach to final speed of 447 m/s after t = 1 min

so we have

v_i = 0

v_f = 447 m/s

t = 1 min = 60 s

so we have

a = \frac{v_f - v_i}{t}

a = \frac{447 - 0}{60}

a = 7.45 m/s^2

7 0
2 years ago
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