Question

a 1 kg ball is confined to move on a. vertical circle of a radius 2 meters. There is no friciton between the bead and the circular track. The bead has a speed of 10 m/s when at the top of the circle at point A, adn the total

Answer 1

The total centripetal force is 50N

Given

mass of the ball= 1kg

speed of the ball = 10m/s

Radius = 2m

we know that

centripetal force = F =$\frac {mv^2}{r}$

F = $\frac {1 \times {10}^2}{2}$ = 50 N

What is Centripetal force?

• A force that causes a body to follow a curved path is known as a centripetal force.
• It always moves in a direction that is the opposite of the body's velocity and in the direction of the immediate center of curvature of the path. It is "a force by which bodies are dragged or driven, or in any other way gravitate, towards a point as to a center," according to Isaac Newton.
• Gravity is the centripetal force that drives astronomical orbits according to Newtonian mechanics.

To learn more about centripetal force with the given link

brainly.com/question/11324711

#SPJ4

Question:

a 1 kg ball is confined to move on a. vertical circle of a radius of 2 meters. There is no friction between the bead and the circular track. The bead has a speed of 10 m/s when at the top of the circle at point A, find the total centripetal force.