Answer: But with that germ-ridden egg comes a mortal danger: Osmosis discovers Frank has really contracted a villainous and black-hearted deadly virus known as Thrax who arrives and is plotting to ultimately overheat Frank's body, killing him from the inside out!
Im not 100% on these but i can try
1. A compound is made up of elements and their different atoms
2.
A. salt- compound (NaCl) is two elements Na (sodium) and Cl (chloride?)
B. Nitrogen- element its on the periodic table
C. Helium- element its on the periodic table
D. Water- compound (H2O) two elements hydrogen and oxygen
3. element, compound, compound, element
Hope this helps
Answer:
The burden distance is 7 ft
Solution:
As per the question:
Specific gravity of package emulsion, 
Specific gravity of diabase rock, 
Diameter of the packaged sticks, d = 3 in
Now,
To calculate the first trail shot burden distance, B:
![B = [\frac{2SG_{E}}{SG_{R}} + 1.5]\times d](https://tex.z-dn.net/?f=B%20%3D%20%5B%5Cfrac%7B2SG_%7BE%7D%7D%7BSG_%7BR%7D%7D%20%2B%201.5%5D%5Ctimes%20d)
![B = [\frac{2\times 1.25}{2.76} + 1.5]\times 3 = 7.22](https://tex.z-dn.net/?f=B%20%3D%20%5B%5Cfrac%7B2%5Ctimes%201.25%7D%7B2.76%7D%20%2B%201.5%5D%5Ctimes%203%20%3D%207.22)
B = 7 ft
Answer:
The distance travel by block before coming to rest is 0.122 m
Explanation:
Given:
Mass of block 
kg
Initial speed of block 
Final speed of block 
Coefficient of kinetic friction 
Ramp inclined at angle 
28.4°
Using conservation of energy,
Work done by frictional force is equal to change in energy,
Where 
m
Therefore, the distance travel by block before coming to rest is 0.122 m
Answer: a. 198.6J b. - 198.6J
Explanation: Parameters given:
m = 15kg
g = 9.8m/s²
∅ = 12°
a. Work done by the force Fp on the cart if the ramp is 6.5m long.
Given the formula, Fp = Mgsin∅ = 15 x 9.8 x sin12° = 30.56N
Therefore Work done (Wp) = Fp x Ramp Length = 30.56 x 6.5 = 198.64Nm or 198.6J
b. The work done by the force mg on the cart.
Since the cart is being pushed upwards, it acts against gravity with its direction of motion. Taking into account the formula from the previous answer for Work Done (Wg) = Fmg x distance
= 15kg x -9.8m/s² x Sin12° x 6.5m
= - 198.6J
