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mixas84 [53]
3 years ago
12

GUYS PLEASE HELP!! The number of individuals that die in a population in a certain time period is the _______ WHAT IS IT!? Pleas

e help someone!
Physics
1 answer:
ryzh [129]3 years ago
3 0
I think it "Death rate" but I am not very sure though.
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When the Glen Canyon hydroelectric power plant in Arizona is running at capacity, 690 m3 of water flows through the dam each sec
igomit [66]

Answer:

The maximum electric power output is P_{max} =1.339*10^{9} \ W

Explanation:

From the question we are told that

        The capacity of the hydroelectric plant is \frac{V}{t}   =  690 \ m^3 /s

         The level at which water is been released is h  =  220 \ m

        The efficiency is  \eta  =0.90

       

The electric power output is mathematically represented as

       P  = \frac{PE_l - PE _o}{t}

Where  PE_l is the potential energy at  level h which is mathematically evaluated as  

          PE_l  =  mgh

and  PE_o  is  the potential energy at ground level which is mathematically evaluated as  

          PE_o  =  mg(0)

         PE_o  =  0

So  

         P  = \frac{mgh}{t}

here  m  =   V *  \rho

where V is volume  and  \rho is density of water whose value is  \rho = 1000 kg/m^3

 So  

         P  = \frac{(\rho * V) * gh}{t}

        P  = \frac{V}{t} * gh \rho

substituting values  

       P  =690 * 9.8 * 220 * 1000

      P  =1.488*10^{9} \ W

The maximum possible electric power output is

           P_{max} = P * \eta

substituting values  

         P_{max} =1.488*10^{9} * 0.90

         P_{max} =1.339*10^{9} \ W

6 0
2 years ago
A 10.00 kg block is placed at the top of a long frictionless inclined plane angled at 37.9 degrees relative to the horizontal. T
NeX [460]

Answer

i dont know

Explanation:

4 0
2 years ago
A projectile of mass 1.800 kg approaches a stationary target body at 4.800 m/s. The projectile is deflected through an angle of
Artyom0805 [142]

Answer:

P = 5.22 Kg.m/s

Explanation:

given,

mass of the projectile = 1.8 Kg

speed of the target = 4.8 m/s

angle of deflection = 60°

Speed after collision = 2.9 m/s

magnitude of momentum after collision = ?

initial momentum of the body = m x v

                                                  = 1.8 x 4.8 = 8.64 kg.m/s

final momentum after collision

momentum along x-direction

P_x = m v cos θ

P_x = 1.8 x 2.9 x  cos 60°

P_x = 2.61 kg.m/s

momentum along y-direction

P_y = m v sin θ

P_y = 1.8 x 2.9 x  sin 60°

P_y = 4.52 kg.m/s

net momentum of the body

P = \sqrt{P_x^2 + P_y^2}

P = \sqrt{4.52^2 + 2.61^2}

 P = 5.22 Kg.m/s

momentum magnitude after collision is equal to P = 5.22 Kg.m/s

5 0
3 years ago
Describe what a hydrogen bond is. 6th grade answer
r-ruslan [8.4K]

Answer:

<em>Hydrogen bond is the attractive force between the hydrogen attached electronegative atom </em>

Explanation:

8 0
3 years ago
Three point charges, two positive and one negative, each having a magnitude of 20 C are placed at the vertices of an equilateral
Daniel [21]

The resultant force on the positive charge  is mathematically given as

X=40N

<h3>What is the magnitude of the electrostatic force on the negative charge?</h3>

Question Parameters:

Three-point charges, two positive and one negative, each having a magnitude of 20

Generally, the -ve charge   is mathematically given as

Q+=\sqrt{x^2+x^2+2x.xcos120}\\\\Q+=\sqrt{2x^2+2x*(1/2)}

Q+=X

Therefore

x=\frac{Kq1q2}{r2}\\\\x=\frac{9*10^9*20*10^{-6}*20*10^{-6}}{(30*10^-2)^2}

X=40N

For more information on Force

brainly.com/question/26115859

5 0
2 years ago
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