Answer:Resistor-Capacitor (RC) circuits, when driven by a voltage/current source, display a type of time-dependent charging or discharging since the charge from the capacitor goes through the resistor. When considering a discharging phase, the time-dependent voltage takes the form
Explanation:
Vt = Voe^-t/RC
Vt equal time dependent voltage
R is the resistance
C is the capacitance of the oscilloscope
Given
Area of capacitor equal to 0.1 * 0.002m
Distance between plates equal 1/1000 = 0.0001m
Vo = 100v supply voltage
Resistance R =:1000ohms
Vt time dependent voltage = 50V
To find capacitance C = Eo(A/d)
C = (8.85 * 10^-12)* (0.002/0.001)
C= 1.77 * 10^-11
Solving the equation Vt = Voe^-t/RC
t = 0.6931RC
t = 0.6931(1000)(1.77*10^-11)
t = 1.2*10^-9
t = 1.2ns
It will take the oscilloscope 1.2ns to reach 50V
Answer:
x = 6136.478 m
y = 2089.2574m
aₓ = 0 m/s²
Explanation:
Given
v₀ = 290 m/s
∅ = 54°
t = 36 s
We can use the formulas
x = v₀*Cos ∅* t = (290 m/s)*Cos (54°)*(36 s) = 6136.478 m
y = y₀ + v₀*Sin ∅*t - 0.5*g*t²
⇒ y = 0 m + (290 m/s)*Sin (54°)*(36 s) - 0.5*(9.81 m/s²)*(36 s)² = 2089.2574m
aₓ = 0 m/s² since vₓ = v₀*Cos ∅ is a constant value.
Answer:
Since the hockey puck is moving at constant velocity
So here we will have
where we have
a = acceleration of the object
m = mass of object
so here since we know that acceleration is defined as rate of change in velocity
so here we will say that
so we have
so we will say that hockey puck is in equilibrium as there is no net force of it
Answer:
Explanation:
, where <em> </em>= avg. velocity, = final velocity, and = initial velocity.
{answer}
The 50N of force would pull the 40N of force, you’d have 10 N of extra force pulling the 40N to the 50N.
{ I hope this helps :) }