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marysya [2.9K]
3 years ago
6

A radioactive nuclide of atomic number emits an electron, then the daughter nuclide emits a gamma ray. What is the atomic number

of the resulting nuclide after both processes?a. Z - 1b. Z + 1c. Z + 2d. Z - 2
Physics
1 answer:
Galina-37 [17]3 years ago
3 0

Answer:

correct answer is b    Z --->Z+1

Explanation:

In the processes of radioactive decay there are three basic processes the emission of alpha particles and the emission of beta rays and the emission of ayos range

The emission of a beta ray implies the transformation of a neutral into a proton, which implies the increase of the atomic number in a unit

          Z   ---->  Z +1

the atomic mass does not change since the mass of the two particles is practically the same, to balance the reaction antineutrino must also be emitted

The daughter particle is in an execrated state and passes to its base state with the emission of a gamma ray that does not change its atomic number or its atomic mass.

Consequently, from the above the correct answer is b

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The law of reflection establishes a definite relationship between the angle of incidence of a light ray striking the boundary be
sladkih [1.3K]

Answer:

The law of reflection states that the angle of incidence = the angle of reflection.

Explanation:

Reflection is the phenomenon that occurs when a ray of light hits the boundary between two media and it is reflected back into the first medium.

In such a situation, we call:

- angle of incidence: it is the angle between the direction of the incident ray and the normal to the surface

- angle of reflection: it is the angle between the direction of the reflected ray and the normal to the surface

There is a precise relationship between the angle of incidence and the angle of reflection. In fact, the Law of Reflection states that:

- The incident ray, the reflected ray and the normal to the surface all lie within the same plane

- The angle of reflection is equal to the angle of incidence

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3 years ago
Changing the direction of current will or will not affect the strength of an electromagnet
jeka57 [31]

Answer:

he polarity of the electromagnet is determined by the direction the current. The north pole of the electromagnet is determined by using your right hand. Wrap your fingers around the coil in the same direction as the current is flowing (conventional current flows from + to -).

Explanation:

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3 years ago
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Est ce qu’un cricket c’est un consommateur
Sholpan [36]

Answer:

Oui

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7 0
3 years ago
George is applying a downward force of 50N to and object that has a mass of 50kg. What is the normal force (FN) of the object wh
attashe74 [19]

The normal force acting on the object is 500 N in the upward direction

<u>Explanation:</u>

As George is applying a downward force, the normal force will be in the upward direction. The normal force will be exerted due to the acceleration due to gravity exerted on the object.

So, as per Newton's second law, the normal force acting on the object can be measured by the product of mass of the object and the acceleration due to gravity acting on the object.

But as the acceleration due to gravity is a downward acting acceleration and the normal force is a upward acting force, so the acceleration will be having a negative sign in the formula.

Normal\ force = Mass \times Acceleration\ due\ to\ gravity

Here, acceleration due to gravity g = -10 m/s² and mass is given as 50 kg, then

Normal force = 50 × (-10) = -500 N

So, the normal force acting on the object is 500 N in the upward direction.

3 0
3 years ago
A rope passes over a fixed sheave with both ends hanging straight down. The coefficient of friction between the rope and sheave
Oliga [24]

Answer:3.51

Explanation:

Given

Coefficient of Friction \mu =0.4

Consider a small element at an angle \theta having an angle of d\theta

Normal Force=T\times \frac{d\theta }{2}+(T+dT)\cdot \frac{d\theta }{2}

N=T\cdot d\theta

Friction f=\mu \times Normal\ Reaction

f=\mu \cdot N

and T+dT-T=f=\mu Td\theta

dT=\mu Td\theta

\frac{dT}{T}=\mu d\theta

\int_{T_2}^{T_1}\frac{dT}{T}=\int_{0}^{\pi }\mu d\theta

\frac{T_2}{T_1}=e^{\mu \pi}

\frac{T_2}{T_1}=e^{0.4\times \pi }

\frac{T_2}{T_1}==e^{1.256}

\frac{T_2}{T_1}=3.51

7 0
3 years ago
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