Answer:
A. It would cause an expansion
Explanation:
Study Island told me the answer ;)
Answer:
The law of conservation of mass indicates the same amount of carbon will be found in the reactants as in the products
Explanation:
The expression that best describes this reaction is that the same amount of carbon will be found in the reactants as in the products.
During the process of photosynthesis, carbon dioxide combines with water using solar energy to produce glucose and oxygen.
It can expressed as depicted below:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
To validate our choice;
This is a balanced chemical equation:
6 moles of carbon is found on the reactant side and also, 6 mole of carbon on the product side.
But Glucose is not found on both sides of the expression
Answer:

Explanation:
We must convert atoms of C to moles of C and then to grams of C.
1. Convert atoms to moles

2. Convert moles to grams

Answer:
1. 75.82 m^3 (cubic meters)
2. 75820 L (Liters)
Explanation:
Given data
L = 21 FT
W = 17 ft
h = 7 ft 6 in
Calculation
Formula to calculate volume is:
V= L×W×h
put the values in formula
V = 21 ft × 17 ft × 7 ft 6 in
V = 2677.5 ft
Now we will convert Cubic ft to cubic meters, as we know that 1 cubic meter is equal to 35.3147 cubic feet
V (m^3) = 2677.5 ÷ 35.3147
V (m^3) = 75.82 m^3
Now we will calculate liters
as we know that 1 cubic meter is equal to 1000 liters
so multiply the ans. with 1000
L = 75.82 × 1000
L = 75820 l
Answer:
1s22s22p6: Neon (Ne)
1s22s22p63s23p3: Phosphorous (P)
1s22s22p63s23p64s1: Potassium (K)
1s22s22p63s23p64s2(im not sure what 308 is supposed to be): Calcium (Ca)
1s22s22p63s23p64s23d104p65s24d3: there is no pure element that ends 4d3 that I know of so this can either be Zirconium(Zr) if it ends in 4d2 or Niobium (Nb) if it ends in 4d4
Explanation:
you can look at the periodic table and the trends to find the rough idea of where the electron configuration ends, there are helpful articles and images on these, i attached an image that may help. After that you can look at the atomic number to find the number of electrons for a pure element and use the electron subshell pattern thing to find the exact number