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emmainna [20.7K]

2 years ago

7

Justify why sound waves need a medium to propagate with example??

1 answer:

Lana71 [14]2 years ago

3 0

Answer:

Sound needs a material medium for their propagation like solid, liquid or gas to travel because the molecules of solid, liquid and gases carry sound waves from one point to another. Sound cannot progress through the vacuum because the vacuum has no molecules which can vibrate and carry the sound waves.

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Two electrons are passing 20.0 mm apart. What is the electric repulsive force that they exert on each other

vladimir1956 [14]

15.0 I’m pretty sure that’s the answer to your question

4 0

2 years ago

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. One long wire carries a current of 30 A along the entire x axis. A second-long wire carries a current of 40 A perpendicular to

d1i1m1o1n [39]

Answer:

magnitude of net magnetic field at given point is

$B = 5 \times 10^{-6} T$

Explanation:

As we know that magnetic field due to a long current carrying wire is given as

$B = \frac{\mu_o i}{2\pi r}$

here we we will find the magnetic field due to wire which is along x axis is given as

$i = 30 A$

r = 2 m

now we have

$B_1 = \frac{4\pi \times 10^{-7} (30)}{2\pi (2m)}$

$B_1 = 3\times 10^{-6} T$ into the plane

Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as

$i = 40 A$

r = 2 m

now we have

$B_2 = \frac{4\pi \times 10^{-7} (40)}{2\pi (2m)}$

$B_2 = 4\times 10^{-6} T$ along + x direction

Since the two magnetic field is perpendicular to each other

So here net magnetic field is given as

$B = \sqrt{B_1^2 + B_2^2}$

$B = 5 \times 10^{-6} T$

5 0

2 years ago

Ice core samples are used to measure…

blsea [12.9K]

Answer:

the correct answer is A

6 0

2 years ago

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After a new aircraft has passed ground and flight tests, the aircraft must receive a series of certificates before it can be mas

ollegr [7]

Answer:

A production certificate Shows that the aircraft met FAA construction and performance standards

Explanation:

Federal Airport Authority (FAA), is the body that check the standard operations of air craft activities in a country.

7 0

3 years ago

It is determined that a certain wave of infrared light has a wavelength of 8.45 mm. Given that c=2.99 ×108 m/s, what is the freq

irina [24]

Answer:

The frequency of infrared wave is 35.385 GHz

Explanation:

Given data:

Wavelength of infrared light = 8.45 mm = 8.45 x $10^{-3}$ m

Velocity of infrared light = 2.99 x $10^{8}$ m/s

To find: frequency of the infrared wave = ?

We know that the wavelength and frequency are inversely proportional and the formula to derive frequency with velocity and wavelength is:

c = μλ, where

c is velocity of light

μ is frequency of light

λ is wavelength of light

Hence the frequency of light μ = c/λ

= $\frac{2.99 x 10^{8} m/s }{8.45 x 10^{-3}m }$

= $\frac{299}{8.45}$ x $10^{9}$ $s^{-1}$

= 35.385 x $10^{9}$ Hz (since 1 $s^{-1}$ = 1 Hz)

= 35.385 GHz

6 0

3 years ago

Read 2 more answers