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emmainna [20.7K]
4 years ago
7

Justify why sound waves need a medium to propagate with example??

Physics
1 answer:
Lana71 [14]4 years ago
3 0

Answer:

Sound needs a material medium for their propagation like solid, liquid or gas to travel because the molecules of solid, liquid and gases carry sound waves from one point to another. Sound cannot progress through the vacuum because the vacuum has no molecules which can vibrate and carry the sound waves.

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The vine has a fixed end, so Tarzan's path is circular. So the vine must not only support Tarzan's weight (or some component of
Minchanka [31]

Answer: hello your question lacks some data attached below is the missing data

answer : T - mg = ma_{c}

Explanation:

Given that the vine has a fixed end and Tarzan's path is circular

At Tarzans lowest point the point can be expressed as shown below.

It can be expressed as : T - mg = ma_{c}

8 0
3 years ago
A 100 kg father and his 50 kg daughter stand on ice skates on a frozen pond. The daughter pushes on her father with a force of 5
Lana71 [14]

Answer:

Both feel same magnitude force.

Explanation:

Given that

Mass of father  = 100 kg

Mass of daughter = 50 kg

From the third law of Newtons :

   Every action have it reaction in opposite direction.It means that if any object apply a force on the other object then first object also feel force of same magnitude but in opposite direction.

It means that both father and her daughter will feel same magnitude of same but in opposite direction.

7 0
4 years ago
Read 2 more answers
In the 1887 experiment by Michelson and Morley, the length of each interferometer arm was 11m. The experimental limit on the mea
Vikentia [17]
For the answer to the question above,
we can get the number of fringes by dividing (delta t) by the period of the light (Which is λ/c). 

fringe = (delta t) / (λ/c) 

We can find (delta t) with the equation: 

delta t = [v^2(L1+L2)]/c^3 

Derivation of this formula can be found in your physics text book. From here we find (delta t): 

600,000^2 x (11+11) / [(3x10^8)^3] = 2.93x10^-13 

2.93x10^-13/ (589x10^-9 / 3x10^8) = 149 fringes 

This answer is correct but may seem large. That is because of your point of reference with the ether which is usually at rest with respect to the sun, making v = 3km/s. 
4 0
3 years ago
A ball falls off the desk and hits the floor. Which
Yuliya22 [10]

Answer:

The potential energy is transformed into kinetic energy

Explanation:

This particular case is defined as the principle of energy conservation since energy is not created or destroyed only transforms. When you have potential energy it can be transformed into kinetic energy or vice versa. In this problem, we have the case of a ball that sits on a desk and then falls to the ground. In this way the ground will be taken as a reference point, this is a point at which the potential energy will be equal to zero in such a way that when the ball is on the desktop that is above the reference line its potential energy will be maximum. As the ball drops its potential energy decreases, as the height relative to the ground (reference point) decreases. In contrast its kinetic energy increases and increases as it approaches the ground. So when it hits the ground it will have maximum kinetic energy and will be equal to the potential energy for when the ball was on the desk.

Therefore:

E_{p} = potential energy [J] = E_{k} = kinetic energy [J]where:\\E_{p} =m*g*h\\m =mass [kg]\\g=gravity[m/s^2]\\h=elevation[m]\\E_{k} = \frac{1}{2} *m*v^{2} \\where:\\v=velocity [m/s]\\\frac{1}{2}  *m*v^{2} = m*g*h

8 0
3 years ago
Although the evidence is weak, there has been concern in recent years over possible health effects from the magnetic fields gene
Natasha2012 [34]

Answer:

A. B = 6.36 * 10^{-10} T

B. P ≈ 0

Explanation:

In order to calculate the magnetic field strength we have to use the magnetic field strength of a straight wire.

B = \frac{mi* I}{2\pi *d} (eq. I)

B = magnetic field strength at distance d

I = current (A)

mi = represented by the greek letter μ, represents the permeability of the free space, which is: 4 × π 10^(-7) T m/A

d = distance from the wire

By replacing the values in eq I, we have the following:

B = \frac{4\pi  10^{-7} T  m  A^{-1}  200 A}{2\pi *20 m}\\\\B = 6.36 * 10^{-10}  T\\ (eq II)

The earth magnetic field in the surface variates from 25 to 65 microteslas. Thus:

P = Percentage from the wires/percentage of the earth

P = \frac{6.36 * 10^{-10}T}{65* 10^{-3} T}\\ ∵ B ∴

P ≈ 0

5 0
4 years ago
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