Answer:
The three dimensions shown in an isometric drawing are the height, H, the length, L, and the depth, D
Explanation:
An isometric drawing of an object in presents a pictorial projection of the object in which the three dimension, views of the object's height, length, and depth, are combined in one view such that the dimensions of the isometric projection drawing are accurate and can be measured (by proportion of scale) to draw the different views of the object or by scaling, for actual construction of the object.
Answer:
the state of the circuit is a function of the voltage level. The interpretation is up to the user.
Explanation:
A binary digital circuit adopts one of two states, depending on whether the voltage level is above or below some threshold that depends on the design of the circuit. Within each state, the voltage may have some typical range. When the voltage is near the threshold, the state of the circuit may actually be "indeterminate".
The internal/output voltage is a function of the state of the circuit. The interpretation of that voltage as a true/false or 1/0 or other meaning is up to the user of the circuit.
The circuit interprets a given input voltage as intending to convey a particular input signal state according to the circuit specifications. Input voltages near the threshold between states may cause unexpected or even destructive results.
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In order to conserve space, some digital circuits use more than 2 different voltage levels to signify more than 2 different states.
Answer:
0.71 lbf
Explanation:
Use ideal gas law:
PV = nRT
where P is absolute pressure,
V is volume,
n is number of moles,
R is universal gas constant,
and T is absolute temperature.
The absolute pressure is the sum of the atmospheric pressure and the gauge pressure.
P = 32 lbf/in² + 14.7 lbf/in²
P = 46.7 lbf/in²
Absolute temperature is in Kelvin or Rankine:
T = 75 + 459.67 R
T = 534.67 R
Given V = 3.0 ft³, and R = 10.731 ft³ psi / R / lb-mol:
PV = nRT
(46.7 lbf/in²) (3.0 ft³) = n (10.731 ft³ psi / R / lb-mol) (534.67 R)
n = 0.02442 lb-mol
The molar mass of air is 29 lbm/lb-mol, so the mass is:
m = (0.02442 lb-mol) (29 lbm/lb-mol)
m = 0.708 lbm
The weight of 1 lbm is lbf.
W = 0.708 lbf
Rounded to two significant figures, the weight of the air is 0.71 lbf.
Answer:
1170 km/hr
Explanation:
Let's first state the formula to be used
c = √(KRT)
The temperature at an altitude of 15km is -56.5° C
Let's not convert this to °K, we have
-56.5° + 273.15 = 216.65° K
Also, the temperature at 8km is -36.9° C, on converting to °K we have
-36.9° + 273.15 = 236.25° K
Then again, we look for the speed at both 15 km and 8 km both of which are 295 m/s and 308 km
Finally, we use the mach similarity formula
(V/c) of 15km = (V/c) of 8km
V of 8km = c of 8km * (V/c) of 15km
V of 8km = 1170 km/hr
