Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Answer:
125,
Step-by-step explanation:
the answer would be fifteen because 5 to the third power is 125.
The perimeter of a rectangle is given by:
P = 2W + 2L
Where,
W: width
L: long
Substituting the values we have to:
P = 2 * (33 + 2 * (3)) + 2 * (39 + 2 * (3))
P = 168 feet
Answer:
joe needs to enclose the garden and path 168 feet of fencing material
1x•4x•5x=180
10x=180
10/10x=180/10
X= 18