Answer:0.302
Explanation:
Given
mass of crate m=27 kg
Force required to set crate in motion is 80 N
Once the crate is set in motion 56 N is require to move it with constant velocity
i.e. 80 N is the amount of force needed to just overcome static friction and 56 is the kinetic friction force
thus

where
is the coefficient of static friction and N is Normal reaction





Complete and Clear Question:
A person puts a few apples into the freezer at -15°C to cool them quickly for guests who are about to arrive. Initially, the apples are at a uniform temperature of 20°C, and the heat transfer coefficient on the surfaces is 8 W/m2·K. Treating the apples as 9-cm-diameter spheres and taking their properties to be
840 kg/m3,
3.81 kJ/kg·K, k = 0.418 W/m·K, and
, determine the center and surface temperatures of the apples in 1 h. Also, determine the amount of heat transfer from each apple. Solve this problem using analytical one-term approximation method (not the Heisler charts).
Answer:
Temperature at the center of the apple, T(t) = 11.215°C
Temperature at the surface of the apple, T(r,t) = 2.68°C
Amount of heat transfer from each apple, Q = 21.47 kJ
Explanation:
For clarity and easiness of expression, the calculations are handwritten and attached as a file. Check the attached files for the complete calculation.
C. Specific gravity is the answer
Sheer tie a very good wjje
Answer:
90 m
Explanation:
Acceleration,
where v and u are final and initial velocities respectively, t is the time taken
Substituting
for a, 4 m/s for u and 10 s for t then
1*10=v-4
v=14 m/s
From kinematic equations

Making s the subject then
