Answer:https://global.oup.com/us/companion.websites/9780199385423/student/ch6/mcq/ just go here
Explanation:
EPA Regulations provides a certified course for the technicians involved in the Air-conditioning system.
Answer: Option (b)
<u>Explanation:</u>
The EPA regulation has implemented an act called the "Clean Air Act" under the "section of 609".
This act provides some basic requirements for EPA Regulation such as follows;
- Refrigerant: This unit must be approved by EPA Regulations before being implemented into the atmosphere.
- Servicing: This system provides a certified course for technicians in service and also approve them with proper refrigerant equipment.
- Reuse Refrigerants: The use of recycled refrigerants must be properly monitored before it comes in to serve.
Measure the longest circuit and add 50% for fittings and terminal units.
Answer:
Eutectic product in Fe-C system is called Ledeburite-C.
Answer:
5984.67N
Explanation:
A 14 inch diameter pipe is decreased in diameter by 2 inches through a contraction. The pressure entering the contraction is 28 psi and a pressure drop of 2 psi occurs through the contraction if the upstream velocity is 4.0 ft/sec. What is the magnitude of the resultant force (lbs) needed to hold the pipe in place?
from continuity equation
v1A1=v2A2
equation of continuity
v1=4ft /s=1.21m/s
d1=14 inch=.35m
d2=14-2=0.304m
A1=pi*d^2/4
0.096m^2
a2=0.0706m^2
from continuity once again
1.21*0.096=v2(0.07)
v2=1.65
force on the pipe
(p1A1- p2A2) + m(v2 – v1)
from bernoulli
p1 + ρv1^2/2 = p2 + ρv2^2/2
difference in pressure or pressure drop
p1-p2=2psi
13.789N/m^2=rho(1.65^2-1.21^2)/2
rho=21.91kg/m^3
since the pipe is cylindrical
pressure is egh
13.789=21.91*9.81*h
length of the pipe is
0.064m
AH=volume of the pipe(area *h)
the mass =rho*A*H
0.064*0.07*21.91
m=0.098kg
(193053*0.096- 179263.6* 0.07) + 0.098(1.65 – 1.21)
force =5984.67N
