1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tema [17]
3 years ago
10

When a switch is closed, an uncharged 151 nF capacitor is connected in a series circuit with a 10.0 x 106 ohm resistor and a 9.0

0 V battery. What is the charge on the capacitor 1.3 s after the switch is closed
Physics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

Explanation:

Given that,

Capacitance of capacitor

C = 151 nF

Resistance of a resistor

R = 10×10^6 ohms

Battery EMF

V = 9V

Charge on capacitor after t = 1.3sec?

This is an RC series circuit

Current in the circuit is given as

i= dq/dt

dq = i•dt

q = ∫i•dt

The voltage in the capacitor is give as

q = CV

Vc = q/C, since q = ∫i•dt

Vc = 1/C ∫i•dt

Therefore applying KVL

Vr + Vc = V.

Vr is voltage across resistor = iR

iR + 1/C ∫i•dt = V

Note that, i=dq/dt and q = ∫i•dt

R dq/dt + q/C = V

Solving this differential equation

Divide through by R

dq/dt + q/RC = V/R

Since, R = 10×10^6 C = 151×10^-9F

Then, dq/dt + q/RC = V/R

dq/dt + q/10×10^6 × 151×10^-9= 9/10×10^6

dq/dt + 0.662q = 9×10^-7

Using integrating factor method

IF = e(0.662t)

So,

q•e(0.662t) = 9×10^-7∫(e(0.662t)dt

q•e(0.662t) = 9 × 10^-7•e(0.662t) / 0.662 + K

q•e(0.662t)=1.36×10^-7•e(0.662t) + K

Divide through by e(0.662t)

q = 1.36×10^-7 + K•e(-0.662t)

At the beginning, there was no charge on the capacitor

q(0) = 0

0 = 1.36 × 10^-7 + k

Then, k = -1.36 ×10^-7

q =1.36×10^-7—1.36×10^-7•e(-0.662t)

Now, at t = 1.3s

q=1.36×10^-7— 1.36 ×10^-7•e(-0.662 × 1.3)

q=1.36×10^-7-1.36×10^-7•e(-0.8606)

q =1.36×10^-7—5.75 × 10^-8

q = 7.85 × 10^-8

Then, q = 78.5 nC

You might be interested in
When you answer someones question how do you make it so your answer is verified??
malfutka [58]
Well YOU cant make your questions verified. if theres more than one answer to the question the person who asked the question will choose the best answer. usually based upon like how well it explains and if its the right answer
6 0
3 years ago
Read 2 more answers
Suppose the line on a distance-versus-time graph and the line on a speed-versus-time graph are both slanted straight lines going
lesya [120]
No, because the distance-time would show a constant velocity but the velocity-time graph shows an increasing velocity.
4 0
4 years ago
Q 1 . How many significant figures are in the following measurement? 0.0009(1 point)
Crazy boy [7]

Here we have some questions about experimental errors.

Q1) We want to see how many significant figures have the measure:

0.0009

The number of significant figures is the number of known digits that are not the leading zeros.

Here we can see four leading zeros, and a single-digit different than zero, which is a 9.

Then we have only one significant figure, the 9.

Q2) Here we will use the measure that is the less exact, as the error of that measure may be larger than the smaller significant figures of the other measures.

Then:

31.2 lb + 38.02lb + 45 lb

The worst measure is 45lb, so the smallest significant figure that we should use is the first one at the left of the decimal point, then we need to round the other two measures to the next whole number, we will get:

31 lb + 38 lb + 45 lb = 114lbs

Q3) We know that the measure is 11.5 seconds and the uncertainty of 1.7%, then the uncertainty will be the 1.7% of the above measure:

(1.7%/100%)*11.5 s = 0.1955 s

Notice that our measure has one significant figure after the decimal point, so we need to round the error to the same significant figure.

0.1955 s ≈ 0.2s

Then the measure is:

11.5 s ± 0.20 s

Q4) We have the measure:

312.0 mph ± 3.9 mph.

The percent uncertainty will be the quotient between the error and the measure times 100%, or:

(3.9 mph/312.0 mph)*100%  = 1.25%

This is a percent error, we do not need to round this.

If you want to learn more, you can read:

brainly.com/question/17339020

5 0
3 years ago
Help pleaseeeeeeeeeeeee
Tasya [4]
A it’s not that hard tbh
7 0
3 years ago
A constant horizontal force F is applied to a 5 kg box on a frictionless horizontal surface. The box starts from rest and moves
sergejj [24]
65(58)+85)6463(9786+)9_43=
7 0
3 years ago
Other questions:
  • An circuit has a section AB as shown in the fig. with E= 10V. (sf C_1) = 1.0 F, (sf C_2) = 2.0 F and the potential difference (s
    9·1 answer
  • A sample neon gas has its volume tripled and its temperature held constant. What will be the new pressure relative to the initia
    5·1 answer
  • n open rectangular tank is filled to a depth of 2 m with water (density 1000 kg/m3). On top of the water there is a 1 m deep lay
    14·1 answer
  • The Sun delivers an average power of 1.575 W/m2 to the top of Neptune's atmosphere. Find the magnitudes of max and max for the e
    7·1 answer
  • A 3250 N car is pushed a distance of 35 m the power was 11375 J, how long did it take?
    11·1 answer
  • (1.5 pts) A woman pushes on a box to the left. If the box is accelerating, what forces are working on the
    15·1 answer
  • What is the kinetic energy of a 1 kg pie if it is thrown at 10 m/s?
    6·1 answer
  • Use this free body diagram to help you find the magnitude of the force needed to keep this block in static equilibrium.
    5·1 answer
  • The reaction K + H2O ⟶ KOH + H2 is an example of?DecompositionSynthesisDouble ReplacementSingle Replacement
    11·1 answer
  •  A baseball is thrown at a speed of Vo at an angle of elevation θ. Determine its range (R) in terms of Vo and θ.​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!