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EleoNora [17]
3 years ago
8

What happens to the molecules when a gas is compressed?

Physics
2 answers:
Daniel [21]3 years ago
5 0

Answer: took the test. Answer is : There is a rise in temperature.

Explanation:

DerKrebs [107]3 years ago
3 0

Answer:

they rise in temperature

Explanation:

when there being compressed theres more pressure causing heat

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Pls help me solve these questions.​
aliina [53]

The value of constant in terms of Force, k, A, V and ρ is  x = ln (F /kAρV ).

<h3>What is opposing force?</h3>

The force which tends to oppose motion of fluid in forward direction like shear stress in liquids and friction force in solids

A body moving through the air at speed V, experiences the retarding force.

Force = kAρVˣ

where A is the surface area, ρ is the density of air and k is the numerical constant.

Taking natural logarithm both sides,

ln F = ln (kAρVˣ)

ln F = x ln (kAρV)

x = ln F / ln (kAρV)

x= ln (F /kAρV )

x= ln F -  ln (kAρV)

Thus, the value of constant is deduced in terms of Force , k, A, V and ρ.

Learn about opposing force.

brainly.com/question/13191643

#SPJ1

5 0
2 years ago
What type of electromagnetic waves do heat lamps give off?
Nitella [24]
Microwaves c…………….nnsjksisisysgxgd
7 0
3 years ago
Read 2 more answers
What is question 22?
Fynjy0 [20]

the answer is a!! its pretty simple I just read the graph.
4 0
3 years ago
Read 2 more answers
The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that
pav-90 [236]

Answer:

The permittivity of rubber is  \epsilon  = 8.703 *10^{-11}

Explanation:

From the question we are told that

     The  magnitude of the point charge is  q_1 =  70 \ nC  =  70 *10^{-9} \  C

      The diameter of the rubber shell is  d = 32 \ cm  =  0.32 \ m

       The Electric field inside the rubber shell is  E =  2500 \ N/ C

The radius of the rubber is  mathematically evaluated as

              r =  \frac{d}{2} =  \frac{0.32}{2}  =  0.16 \ m

Generally the electric field for a point  is in an insulator(rubber) is mathematically represented as

         E =  \frac{Q}{ \epsilon }  *  \frac{1}{4 *  \pi r^2}

Where \epsilon is the permittivity of rubber

    =>     E  *  \epsilon  *  4 * \pi *  r^2 =  Q

   =>      \epsilon  =  \frac{Q}{E *  4 *  \pi *  r^2}

substituting values

            \epsilon  =  \frac{70 *10^{-9}}{2500 *  4 *  3.142 *  (0.16)^2}

            \epsilon  = 8.703 *10^{-11}

7 0
3 years ago
Does changing position of charges change the magnitude
hodyreva [135]

Answer:

No, they will not change.

Explanation:

7 0
3 years ago
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