Two loudspeakers emit 600 Hz Hz notes. One speaker sits on the ground. The other speaker is in the back of a pickup truck. You h
1 answer:
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Note: I assume the mirror is concave, so that its focal length is positive (it is not specified in the text)
1a) We can use the mirror equation to find the distance of the image from the mirror:
where
is the focal length
is the distance of the object from the mirror
is the distance of the image from the mirror.
Rearranging the equation, we find
so, the distance of the image from the mirror is
.
1b) The image height is given by the magnification equation:
where
is the heigth of the image and 
is the height of the object. By rearranging the equation and using p and q, we find
and the negative sign means the image is inverted.
2) As before, we can find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
3) As before, we find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
And now we can use the magnification equation to find the image height:
Rearranging it, we find
and the negative sign means the image is inverted.
1a) We can use the mirror equation to find the distance of the image from the mirror:
where
Rearranging the equation, we find
so, the distance of the image from the mirror is
1b) The image height is given by the magnification equation:
where
and the negative sign means the image is inverted.
2) As before, we can find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
3) As before, we find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
And now we can use the magnification equation to find the image height:
Rearranging it, we find
and the negative sign means the image is inverted.
Explanation :
It is given that, a heavy box is in the back of a truck and the truck is accelerating to the right.
The description is shown in<em> figure 1</em>. Here, the forces that act on both box and the truck are the normal force, the frictional force and their weight mg.
The free body diagram is shown in <em>figure 2</em>. This shows the total forces ( F = ma )acting on the truck. As a result, the truck will move in a forward direction.
Hence, this is the required explanation.
