A spring is compressed 0.035 m inside a dart gun. (K=500 N/m). The spring has elastic energy. Calculate it.
1 answer:
The elastic potential energy of the spring is 0.31 J
Explanation:
The elastic potential energy of a spring is given by
where
k is the spring constant
x is the compression/stretching of the spring
For the spring in this problem, we have:
k = 500 N/m (spring constant)
x = 0.035 m (compression)
Substituting, we find the elastic potential energy:
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Answer:
The extension of the second wire is
Explanation:
From the question we are told that
The length of the wire is
The elongation of the wire is
The tension is
The length of the second wire is
Generally the Young's modulus(Y) of this material is
Where
Where A is the area which is evaluated as
and
So
Since the wire are of the same material Young's modulus(Y) is constant
So we have
Now the ration between the first and the second wire is
Since tension , radius are constant
We have
substituting values