<span>when two containers at the same temperature are brought together, no heat is transferred.
It is true
</span>
Answer:
5.90000114e+7 m/s
Explanation:
Given values
M₁ = 1.8e+8 kg
M₂ = 2.4e+25 kg
M = M₁ + M₂ = 2.400000000000000018e+25 kg
G = 6.6743e-11 m³ kg⁻¹ sec⁻²
GM = 1.60183200000000001201374e+15 m³ sec⁻²
r₁ = 2.9e+7 m
v₁ = 5.9e+7 m/s
R = 2.2e+6 m
The total energy of the meteroid per unit mass at time t₁ is
E/M₁ = 0.5v₁² − GM/r₁ = 1.7404999447644137931034478615952e+15 m²/s²
At impact,
E/M₁ = 0.5v₂² − GM/R = 1.7404999447644137931034478615952e+15 m²/s²
v₂ = √[2(E/M₁ + GM/R)] = 5.9000011404572937396882314817886e+7 m/s
v₂ − v₁ ≈ 11.4 m/s
Answer:
Largest; options A & B
2nd largest; Option F
3rd Largest; Option D
Smallest; Options E & C
Explanation:
Looking at the charges, basically, the net force of the charge q1 is the sum of charges q2 and q3.
When 2 charges are opposite, the force will be attractive but if they are same, then the force will be repulsive.
Thus, the order of the forces is;
I) Largest: q1= +1nC, q2= -1nc, q3= -1nc and (q1= -1nC, q2= +1nc, q3= +1nc)
II) Second largest is: q1= +1nC, q2= -1nc, q3= +1nc
III) Third largest: q1= +1nC, q2= +1nc, q3= -1nc
IV) Smallest: (q1= -1nC, q2= -1nc, q3= -1nc) and (q1= +1nC, q2= +1nc, q3= +1nc)
The gravitational force of the shell exerts is 4.25m x 10¯¹² N.
We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses of objects. The magnitude of gravitational force can be determined as
F = G.m1.m2 / R²
where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.
From the question above, we know that
m1 = 1.6 kg
m2 = m
R = 5.01 m
By substituting the following parameters, we get
F = G.m1.m2 / R²
F = 6.674 × 10¯¹¹ . 1.6 . m / 5.01²
F = 4.25m x 10¯¹² N
where m is the mass of the shell
For more on gravitational force at: brainly.com/question/19050897
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I believe the answer is 7.24 kJ.
From the equation ΔE = dW + dQ; where W is the work done on/by the system and Q is the heat the system absorbs/loses.
Therefore; ΔE = 72.4 kJ since the system has bot done any p-v work (dV= zero) and has absorbed heat.