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maw [93]
3 years ago
8

Help me help me!!!!!!!

Mathematics
1 answer:
neonofarm [45]3 years ago
8 0
The answer is B. -x^3+2x^2-3x+10
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Solve the system of the linear equation using any method:<br> 2x+5y=4<br> 4x+7y=11
mr_godi [17]
Multiply the first equation by 2:
4x+10y=8
Subtract the second equation from this so the 4x cancels:
3y = -3
y = -1
Plug into first equation:
2x -5 = 4
2x = 9
x = 9/2 = 4 1/2 = 4.5
So (x,y) = (-1,4.5)
3 0
3 years ago
Read 2 more answers
In a University of Wisconsin (UW) study about alcohol abuse among students, 100 of the 40,858 members of the student body in Mad
dimaraw [331]

Answer:

a) The population is 40,858 students and the sample is 100.

b) No

Step-by-step explanation:

a) The population would be the 40,858 members of the student body. Since we are only applying the questionnaire to 100 students, the sample would be 100.

b) 29% of the students answered "zero" to the question on how many days in the past week they consumed at least one alcoholic drink. This means that 29 out of 100 students gave this answer. However, this doesn't mean that 29% of the entire population of UW would give this response. Why is that? Because our sample is very small so it might not be representative of the whole population. Equally, the results from such a sample cannot be exactly the same results we would get from an entire population.

7 0
3 years ago
Can somebody help me with this
Lubov Fominskaja [6]
Nope lol , don't even know what the dang
question is

8 0
4 years ago
How to find an decimal out of percentage
irinina [24]

To convert a decimal to a percent, multiply the decimal by 100, then add on the % symbol. An easy way to multiply a decimal by 100 is to move the decimal point two places to the right.

7 0
3 years ago
5y^2+5−4−4y^2+5y^2−4x^3 −1
vredina [299]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{4 {x}^{3}  + 6 {y}^{2} }}}}}

Step-by-step explanation:

\sf{5 {y }^{2}  + 5 - 4 - 4 {y}^{2}  + 5 {y}^{2}  - 4 {x}^{3}  - 1}

Collect like terms

⇒\sf{ 4 {x}^{3}  + 5 {y}^{2}  - 4 {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  +  {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 5 - 4 - 1}

Calculate

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 1 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2} }

Hope I helped!

Best regards! :D

6 0
3 years ago
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