Answer:
2.5 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have two different values of V and P:
<em>P₁V₁ = P₂V₂
</em>
P₁ = 5.0 atm, V₁ = 3.5 L.
P₂ = 7.0 atm, V₂ = ??? L.
<em>∴ V₂ = P₁V₁/P₂ </em>= (5.0 atm)(3.5 L)/(7.0 atm) = <em>2.5 L.
</em>
The ratio of the diffusion rate of Cl2 and O2 is 1.5
calculation
rate of diffusion Cl2/ rate of diffusion O2 =√ molar mass of Cl2/ molar mass of O2
molar mass of Cl2 = 35.5 x2 = 71 g/mol
molar mass O2 = 16 x2 =32g/mol
that is rate of diffusion Cl2/ rate of diffusion of O2 =√ 71/ 32= 1.5
Answer:
P(total) = 1110 mmHg
Explanation:
According to the Dalton law of partial pressure,
The pressure exerted by mixture of gases are equal to the sum of partial pressure of individual gases.
P(total) = P1 + P2 + P3+ .....+ Pn
Given data:
Sample A = 740 mmHg
Sample B = 740 mmHg
Sample C = 740 mmHg
Total pressure = ?
Solution:
<em>Sample A:</em>
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 740 mmHg × 2L/4L
P₂ = 370 mmHg
<em>Sample B:</em>
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 740 mmHg × 2L/4L
P₂ = 370 mmHg
<em>Sample C:</em>
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 740 mmHg × 2L/4L
P₂ = 370 mmHg
Total pressure:
P(total) = P1 + P2 + P3
P(total) = 370 mmHg + 370 mmHg+ 370 mmHg
P(total) = 1110 mmHg
Copper Sulfate (CuSO4) compound is basically comprised of Copper (II) ion and Sulfate ion. Ions are C<span>u2</span>+ and S<span>O4 2</span><span>−</span>.
<em>ANSWER:</em><em>Cu 2+ and SO4 2-</em>