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2 years ago

What is the ratio of the diffusion rates of cl2 and o2? rate cl2 : o2 = 0.47 0.67 0.45 0.69 1.5?

1 answer:

7 0

The ratio of the diffusion rate of Cl2 and O2 is 1.5

calculation
rate of diffusion Cl2/ rate of diffusion O2 =√ molar mass of Cl2/ molar mass of O2

molar mass of Cl2 = 35.5 x2 = 71 g/mol
molar mass O2 = 16 x2 =32g/mol

that is rate of diffusion Cl2/ rate of diffusion of O2 =√ 71/ 32= 1.5

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Why is sodium more reactive than lithium

Elis [28]

Answer:

Sodium is more reactive than lithium because as we move down a group it is easy to lose electrons as the number of shells increases and nuclear charge decreases. As valence electrons take part in chemical reaction and its easier to lose electrons as we move down a group chemical reactivity increases. Therefore, sodium is more reactive than lithium.

Explanation:

I gotcha I searched it up

4 0

3 years ago

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A sample compound contains 9.11 g Ni and 5.89g F. What is the empirical formula of this compound?

Alexxx [7]

The empirical formula of the compound is C. NiF₂.

Step 1. Calculate the moles of each element

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Ni to F.

Moles of Ni = 9.11 g Ni × (1 mol Ni /(58.69 g Ni) = 0.1552 mol Ni

Moles of F = 5.89 g F × (1 mol F/19.00 g F) = 0.3100 mol F

Step 2. Calculate the molar ratio of the elements

Divide each number by the smallest number of moles

Ni:F = 0.1552:0.3100 = 1:1.997 ≈ 1:2

Step 3: Write the empirical formula

EF = NiF₂

8 0

3 years ago

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slader Consider the following reactions: A. uranium-238 emits an alpha particle; B. plutonium-239 emits an alpha parti- cle; C.

pishuonlain [190]

Answer:

For A: The equation is $_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha$

For B: The equation is $_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha$

For C: The equation is $_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta$

Explanation:

Alpha decay process is the process in which nucleus of an atom disintegrates into two particles. The first one which is the alpha particle consists of two protons and two neutrons. This is also known as helium nucleus. The second particle is the daughter nuclei which is the original nucleus minus the alpha particle released.

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha$

Beta decay process is defined as the process the neutrons get converted into an electron and a proton. The released electron is known as the beta particle. In this process, the atomic number of the daughter nuclei gets increased by a factor of 1 but the mass number remains the same.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

For A: Uranium-238 emits an alpha particle

The nuclear equation for this process follows:

$_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha$

For B: Plutonium-239 emits an alpha particle

The nuclear equation for this process follows:

$_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha$

For C: Thorium-239 emits a beta particle

The nuclear equation for this process follows:

$_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta$

6 0

3 years ago

The blood cells that directly attack germs are: *

irga5000 [103]

Answer:

lymphocytes

Explanation:

it consists of the b and the t cells

4 0

3 years ago

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How much pure acid is in 520 milliliters of a 13 % solution?

Liono4ka [1.6K]

It actually depends on the percentage of the concentration give. Percentages can be expressed as %mass/mass, %volume/volume or %mass/volume. To keep things simple, let's just assume that it is in %volume/volume. Thus, 13% of 520 mL is pure acid.

Volume of pure acid = 520*0.13 = 67.6 mL

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2 years ago