Answer:
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1) Use of density formula to calculate mass of sample, M
D = M / V => M = D* V = 0.9977 g / mL * 50.00 mL = 49.885 g of sample
Realize that the sample is the solution.
2) Use ppm concentration to calculate mass of solute (calcium carbonate)
By definition, 75.0 ppm = 75.0 g of calcium carbonate / 1,000,000 g of solution.
You use that ratio to calculate the mass of calcium carbonate in 49.885 g of solution.
Mass of solute = 49.885 g of solution * [75.0 g of calcium carbonate] / [1,000,000 g of solution] =
Mass of solute = 0.00374 g of calcium carbonate
Answer: 0.00374 g of calcium carbonate
Answer:
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Explanation:
Answer:
Most similar - Lithium
Least similar - Phosphorus
Explanation:
Rubidium is an element in group 1A of the periodic table. It is a metal and forms an ionic compound with chlorine. The formula of the compound is RbCl.
If we look at the options, Lithium is also a group 1A element and forms an ionic compound with chlorine having the formula LiCl which is very much similar to RbCl chemically.
Phosphorus is a nonmetal. Its compounds with chlorine, PCl3 and PCl5 are covalent and does not resemble RbCl in any way.