The second brother Brother because he is much heavier and therefore has more energy to be released hope this helps
Answer: 19.4 g/cm3
Explanation: density is the relationship between mass over volume.
So density of gold is 15.7g/0.81cm3 = 19.4 g/cm3
CaBr2(s) Ca+2(aq)+2Br-(aq) which means, <span>Solid is turning into free ions so entropy is increasing .</span>
Answer: The equivalent mass of the acid is 83.16 grams
Explanation:
To calculate the number of moles for given molarity, we use the equation:
Molarity of
solution = 0.1165 M
Volume of
solution = 24.68 mL = 0.02468 L
Putting values in equation 1, we get:
( as acidity of NaOH is 1)
For end point: gram equivalents of acid = gram equivalents of base = 
Mass of acid=


Thus equivalent mass of the acid is 83.16 grams
Answer : The equilibrium concentration of
will be, (C) 
Explanation : Given,
Equilibrium constant = 14.5
Concentration of
at equilibrium = 0.15 M
Concentration of
at equilibrium = 0.36 M
The balanced equilibrium reaction is,

The expression of equilibrium constant for the reaction will be:
![K_c=\frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
Now put all the values in this expression, we get:
![14.5=\frac{[CH_3OH]}{(0.15)\times (0.36)^2}](https://tex.z-dn.net/?f=14.5%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%280.15%29%5Ctimes%20%280.36%29%5E2%7D)
![[CH_3OH]=2.82\times 10^{-1}M](https://tex.z-dn.net/?f=%5BCH_3OH%5D%3D2.82%5Ctimes%2010%5E%7B-1%7DM)
Therefore, the equilibrium concentration of
will be, (C) 