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arsen [322]
3 years ago
6

A white blood cell has a diameter of approximately 12 micrometers, or 0.012 um. A model represents its diameter as 24 um. What i

s the ratio of model size to actual size?
Physics
1 answer:
GuDViN [60]3 years ago
8 0

Answer:

2:1

Explanation:

It is given that,

The diameter of a white blood cell is 12 micrometers

The diameter of white blood cell according to a model is 24 micrometers.

We need to find the ratio of model size to actual size. It can be done as follows :

R=\dfrac{\text{model size}}{\text{actual size}}\\\\R=\dfrac{24\ \mu m}{12\ \mu m}\\\\R=\dfrac{2}{1}

Hence, the ratio of model size to actual size is 2:1.

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Answer:

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Explanation:

if correct plzz brainliest :D

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The question is in the picture
Sedbober [7]

Answer:

e) 120m/s

Explanation:

When the ball reaches its highest point, its velocity becomes zero, meaning

v_0-gt = 0.

where v_0 is the initial velocity.

Solving for t we get

t = \dfrac{v_0}{g}

which is the time it takes the ball to reach the highest point.

Now, after the ball has reached its highest point, it turns around and falls downwards. After time t_0 since it had reached the highest point, the ball has traveled downwards and the velocity v_f it has gained is

v_f = gt_0,

and we are told that this is twice the initial velocity v_0; therefore,

v_f = 2v_0  = gt_0

which gives

t_0 = \dfrac{2v_0}{g}.

Thus, the total time taken to reach velocity 2v_0 is

t_{tot} = t+t_0 = \dfrac{v_0}{g}+\dfrac{2v_0}{g}

t_{tot} = \dfrac{3v_0}{g}.

This t_{tot}, we are told, is 36 seconds; therefore,

36= \dfrac{3v_0}{g},

and solving for v_0 we get:

v_0 = \dfrac{36g}{3}

v_0 = \dfrac{36s(10m/s^2)}{3}

\boxed{v_0 = 120m/s}

which from the options given is choice e.

7 0
3 years ago
Is Mercury a heavier element than tin
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Which telescope would be better viewing a faint, distant star? Why?
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Reflecting telescope. Reflecting telescopes tend to have larger objective (due to the use of mirrors, mirrors are a lot cheaper than lenses) and have the ability to collect more light, while refracting telescopes are limited to objective lenses with smaller diameters due to their structural limitations (chromatic abbreviation, for example). Therefore, reflecting telescopes should be better at viewing faint distant stars
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A 6.0-kilogram cart initially traveling at 4.0 meters per second east accelerates uniformly at 0.50 meter per second squared eas
VMariaS [17]

Answer: 5.5m/s

Explanation:

vf=vi+at

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