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Aneli [31]
3 years ago
6

How does an engine convert fuel into a useful form of energy

Engineering
1 answer:
crimeas [40]3 years ago
5 0

Answer:

Combustion.

Explanation:

The engine takes the fuel and sets fire to it. This induces movement in the pistons, which powers everything in the vehicle. This is why it usually takes a second to power up a vehicle. Especially in cold weather.

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Heey

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What should i do to my nissan 350z, twin charge it or have twin turbos, to twin turbos with a super charger? i want it to be ove
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A farmer has 19 sheep on his land. One day, a big storm hits and all but seven run away. How many sheep does the farmer have lef
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3 years ago
What is a perpetual motion machine of the second kind?
d1i1m1o1n [39]

Answer:

perpetual motion machine of second type is a machine that generates job from a single source of heat.

Explanation:

perpetual motion machine is a machine that generates job from a single source of heat. only one heat reservoir is present in this type of machine and it is continuously cooled to generate function without transferring heat to a cooler reservoir. Such a demonstration machine was names as ammonia engine

5 0
3 years ago
A metal plate of 400 mm in length, 200mm in width and 30 mm in depth is to be machined by orthogonal cutting using a tool of wid
dmitriy555 [2]

Complete Question:

A metal plate of 400 mm in length, 200mm in width and 30 mm in depth is to be machined by orthogonal cutting using a tool of width 5mm and a depth of cut of 0.5 mm. Estimate the minimum time required to reduce the depth of the plate by 20 mm if the tool moves at 400 mm per second.

Answer:

T_{min} = 26 mins 40 secs

Explanation:

Reduction in depth, Δd = 20 mm

Depth of cut, d_c = 0.5 mm

Number of passes necessary for this reduction, n = \frac{\triangle d}{d_c}

n = 20/0.5

n = 40 passes

Tool width, w = 5 mm

Width of metal plate, W = 200 mm

For a reduction in the depth per pass, tool will travel W/w = 200/5 = 40 times

Speed of tool, v = 100 mm/s

Time/pass = \frac{40*400}{400} \\Time/pass = 40 sec

minimum time required to reduce the depth of the plate by 20 mm:

T_{min} = number of passes * Time/pass

T_{min} = n * Time/pass

T_{min} = 40 * 40

T_{min} =  1600 = 26 mins 40 secs

3 0
4 years ago
Read 2 more answers
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