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madam [21]
1 year ago
9

Hole filling fasteners (for example, MS20470 rivets) should not be used in composite structures primarily because of the

Engineering
1 answer:
DanielleElmas [232]1 year ago
3 0

Option c is correct. Hole filling fasteners (for example, MS20470 rivets) should not be used in composite structures primarily because of the  increased possibility of fretting corrosion in the fastener.

Fretting corrosion is the outcome of simultaneous physicochemical and mechanical surface interaction in a tribological contact, and it is the irreversible change of a material. A specific load and cyclic displacement with a limited amplitude must be applied to the contact between the surfaces of two materials for fretting corrosion to take place.

Small gaps develop between the surfaces in contact as a result of cyclic tension. Either material is lost or cracks start to appear as a result. Fretting corrosion's side effect of contact corrosion almost always causes a blockage because the lack of functional movement makes it impossible to remove debris. When debris is still trapped, there is blockage because the oxide takes up more space than the original material.

To know more about functional click here:

brainly.com/question/9171028

#SPJ4

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Compute the sum with carry-wraparound (sometimes called the one's complement sum) of the following two numbers. Give answer in 8
leonid [27]

Answer:

00100111

Explanation:

Given;

10010110

10010000

Add these like normal binary numbers

10010110

10010000

-------------

(1)00100110

-------------

ignore extra (1) on left since it's a carry.

Add 1 to the above result to make it a 1's complement result

00100110 + 1 = 00100111

Answer: 00100111

3 0
4 years ago
1. Round off 2553 N to three significant figures.
Marizza181 [45]

Answer:

(1) 2553 N = 2550 N

(2) 58342 m = 58300 m

(3) 68.534 s = 68.5 s

Explanation:

To round off a number to any significant number start from the last digit, round it off to 1 if the number is up to 5 and to 0 if the last digit is less than 5. Add this 1 or 0 to the preceding digit and continue the process until you are left with three non zero digits, if you are rounding off to three significant figures.

(1) Round off 2553 N to three significant figures.

= 2550 N

(2) Round off 58342 m to three significant figures.

= 58300 m

(3) Round off 68.534 s to three significant figures.

= 68.500 s (zero after decimal point is insignificant)

= 68.5 s

8 0
4 years ago
A turbojet is flying with a velocity of 900 ft/s at an altitude of 20,000 ft, where the ambient conditions are 7 psia and 10°F.
tino4ka555 [31]

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3 0
4 years ago
A pin-supported structure has unrestrained rotations at the support locations.a) True b) False
antoniya [11.8K]

Answer:

a)True

Explanation:

Yes it is true a pin support can not resist the rotation motion . It can resist only lateral or we can say that only linear motion of structure and can not resit angular moment of motion about hinge or pin joint.On the other hand a fixed support can resist linear as well rotation motion of structure.

6 0
3 years ago
The supplement file* that enclosed to this homework consists Time Versus Force data. The first column in the file stands for tim
AysviL [449]

Answer:

A.) 1mv = 2000N

B.) Impulse = 60Ns

C.) Acceleration = 66.67 m/s^2

Velocity = 4 m/s

Displacement = 0.075 metre

Absorbed energy = 60 J

Explanation:

A.) Using a mathematical linear equation,

Y = MX + C

Where M = (2000 - 0)/( 898 - 0 )

M = 2000/898

M = 2.23

Let Y = 2000 and X = 898

2000 = 2.23(898) + C

2000 = 2000 + C

C = 0

We can therefore conclude that

1 mV = 2000N

B.) Impulse is the product of force and time.

Also, impulse = momentum

Given that

Mass M = 30kg

Velocity V = 2 m/s

Impulse = M × V = momentum

Impulse = 30 × 2 = 60 Ns

C.) Force = mass × acceleration

F = ma

Substitute force and mass into the formula

2000 = 30a

Make a the subject of formula

a = 2000/30

acceleration a = 66.67 m/s^2

Since impulse = 60 Ns

From Newton 2nd law,

Force = rate of change in momentum

Where

change in momentum = -MV - (- MU)

Impulse = -MV + MU

Where U = initial velocity

60 = -60 + MU

30U = 120

U = 120/30

U = 4 m/s

Force = 2000N

Impulse = Ft

Substitute force and impulse to get time

60 = 2000t

t = 60/2000

t = 0.03 second

Using third equation of motion

V^2 = U^2 + 2as

Where S = displacement

4^2 = 2^2 + 2 × 66.67S

16 = 4 + 133.4S

133.4S = 10

S = 10/133.4

S = 0.075 metre

D.) Energy = 1/2 mV^2

Energy = 0.5 × 30 × 2^2

Energy = 15 × 4 = 60J

5 0
4 years ago
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