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IgorLugansk [536]
3 years ago
7

During an ionic bond, electrons are basically transferred from one atom to another whereas in a covalent bond, electron pairs ar

e shared. true or false
Chemistry
1 answer:
Ad libitum [116K]3 years ago
8 0
The answer is true......

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Li2SO4 _____ an electrolyte in solution.<br> A. Is <br> B. Is not
Rasek [7]

Answer:

a

Explanation:

it is an electrolyte because of its strong polar chemical bond

8 0
3 years ago
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Stainless steel is an alloy of iron containing 5 percent nickel and 0.175 percent chromium. How many atoms of nickel are present
erica [24]
First you need to work out what mass of 84g of stainless steel is nickel, and because there's 5% you can simply divide by 20, giving 4.2g

For this you can use the equation Moles= \frac{Mass}{Mr}

The mass, as was worked out previously, is 4.2g
The Mr, which is found on the periodic table, is 28

Moles = \frac{4.2}{28} = 0.15mol

1mol = 6.023 x 10^{23} atoms

So, 0.15mol = 0.15 x 6.023 x 10^{23} = 9.0345 x 10^{22} atoms


3 0
4 years ago
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Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group.
Serjik [45]

I think the correct answer would be the last one.

7 0
3 years ago
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3 waves are shown with a line through their center. The bottom of the first wave is labeled C. A bracket labeled D connects the
Likurg_2 [28]

Answer:Label the parts of this wave.

A:  

✔ crest

B:  

✔ amplitude

C:  

✔ trough

D:  

✔ wavelength

Explanation:

8 0
3 years ago
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The half-life of tritium (H-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a
Rudiy27

Answer:

The amount left after 49.2 years is 3mg.

Explanation:

Given data:

Half life of tritium = 12.3 years

Total mass pf tritium = 48.0 mg

Mass remain after 49.2 years = ?

Solution:

First of all we will calculate the number of half lives.

Number of half lives = T elapsed/ half life

Number of half lives =  49.2 years /12.3 years

Number of half lives =  4

Now we will calculate the amount left after 49.2 years.

At time zero 48.0 mg

At first half life = 48.0mg/2 = 24 mg

At second half life = 24mg/2 = 12 mg

At 3rd half life = 12 mg/2 = 6 mg

At 4th half life =  6mg/2 = 3mg

The amount left after 49.2 years is 3mg.

6 0
3 years ago
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