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3 years ago

What is the second quantum number of a 2s^2 electron in phosphorus,

Chemistry

1 answer:

My name is Ann [436]3 years ago

8 0

Answer:

l = 0

Explanation:

Second quantum number, also known as angular momentum quantum number (l), represents the shape of an orbital. Several quantum numbers and their corresponding orbital shapes are worth remembering:

l = 0, this is an s-shaped orbital;
l = 1, this is a p-shaped orbital;
l = 2, this is a d-shaped orbital;
l = 3, this is a f-shaped orbital

Notice that the angular momentum quantum number might be identified solely from the letter. Since we're considering a $2s$ orbital, this means we're dealing with an s orbital. As defined above, s-shaped orbital would have an l value of l = 0.

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) The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully equalizing

Oksana_A [137]

Answer:

P (H₂) = 741 torr

Explanation:

Let's begin by listing out the given parameters:

Temperature (water) = 298 K, volume = 45.6 mL,

atmospheric pressure, P (total) = 765 torr, vapor pressure of water, P (H₂O) = 24 torr

To get the pressure of inside the tube, P (H₂), we apply Dalton's Law of Partial Pressure and we have:

P (total) = P (H₂) + P (H₂O)

P (total) = 765 torr, P (H₂O) = 24 torr

P (H₂) = P (total) - P (H₂O) = 765 - 24

P (H₂) = 741 torr

It therefore becomes clear that the pressure of H₂(g) is 741 torr

3 0

3 years ago

Identify the type of interactions involved in each of the following processes taking place during the dissolution of sodium chlo

icang [17]

Answer:

A. Interactions between the ions of sodium chloride (solute-solute interactions).

B. Interactions involving dipole-dipole attractions (solvent-solvent interactions).

C. Interactions formed during hydration (solute-solvent interactions).

D. Interactions involving ion-ion attractions (solute-solute interactions).

E. Interactions associated with an exothermic process during the dissolution of sodium chloride (solute-solvent interactions).

F. Interactions between the water molecules (solvent-solvent interactions).

G. Interactions formed between the sodium ions and the oxygen atoms of water molecules (solute-solvent interactions).

Explanation:

The solution process takes place in three distinct steps:

Step 1 is the separation of solvent molecules.

Step 2 entails the separation of solute molecules.

These steps require energy input to break attractive intermolecular forces; therefore, they are endothermic.

Step 3 refers to the mixing of solvent and solute molecules. This process can be exothermic or endothermic.

If the solute-solvent attraction is stronger than the solvent-solvent attraction and solute-solute attraction, the solution process is favorable, or exothermic (ΔHsoln < 0). If the solute-solvent interaction is weaker than the solvent-solvent and solute-solute interactions, then the solution process is endothermic (ΔHsoln > 0).

In the dissolution of sodium chloride, this process is exothermic.

3 0

3 years ago

HELP ME ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!

Kobotan [32]

Answer:

Digestive

Explanation:

7 0

3 years ago

Which of the following atoms is likely to transfer (and lose) an electron when it forms an ion? Please choose the correct answer

mestny [16]

Answer:

An atom containing 11 electrons

Explanation:

Metal atoms form ions by a loss of electrons whereas non-metal atoms form ions by the gain of electrons.

The group 1 elements or alkali metals form lose their one valence shell electrons when forming ions; Group 2 metals lose two while Group 3 lose three. On the other hand, non-metal atoms found in Group 5, 6, and 7 forms ions by gaining one, two and three electrons respectively.

Using the electronic configuration of atoms, their groups in the Periodic Table can be determined.

An atom containing 6 electrons has the configuration 2,4 and thus belongs to Group 4.

An atom with 2 electrons belongs to Group 2

An atom with 11 electrons has the configuration 2,8,1 and thus belongs to Group 1

An atom with 10 electrons has the configuration 2,8 and thus belongs to Group 8

An atom with 8 electrons has the configuration 2,6 and thus belongs to Group 6.

From the above, it can be seen that an atom containing 11 electrons belongs to Group 1 and will lose an electron to form an ion.

8 0

3 years ago

The properties of two elements are listed below. Element Atomic radius (pm) Ionic radius (pm) First ionization energy (kJ/mol) E

Sedbober [7]

Answer:

K will give up an electron more easily than Br.

Explanation:

Electronegativity of an element is a property that combines the ability of its atom to lose and gain electrons.

The lower the electronegativity value, the more electropositive an element is and the more readily it loses electrons.

From the data given, we see that Br has an E.N value of 3.0 and K has an E.N value of 0.82.

Therefore, Br is highly electronegative and it is able to attract electrons to itself whereas K has a low E.N value. K will give up electrons more readily.

Lookinf at other information in the table, the larger atomic radius and lower ionizaton energy of K are all pointers to how readily it would be able to lose electrons.

We can conclude that K is even a metal.

5 0

3 years ago