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2 years ago

What is the second quantum number of a 2s^2 electron in phosphorus,

Chemistry

1 answer:

My name is Ann [436]2 years ago

8 0

Answer:

l = 0

Explanation:

Second quantum number, also known as angular momentum quantum number (l), represents the shape of an orbital. Several quantum numbers and their corresponding orbital shapes are worth remembering:

l = 0, this is an s-shaped orbital;
l = 1, this is a p-shaped orbital;
l = 2, this is a d-shaped orbital;
l = 3, this is a f-shaped orbital

Notice that the angular momentum quantum number might be identified solely from the letter. Since we're considering a $2s$ orbital, this means we're dealing with an s orbital. As defined above, s-shaped orbital would have an l value of l = 0.

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If 125 ml of o2 gas exerts a pressure of 1.0 atm inside a cylinder, what will the pressure be if the cylinder compressed the vol

Lelu [443]

<h2>Hello!</h2>

The answer is: The new pressure is 1.67 atm.

From the statement, we know that the temperature remains constant and the gas volume is changing, meaning that the new pressure will be different than the first pressure.

Since the temperature remains constant, we can calculate the new pressure using the Boyle's Law.

The Boyle's Law states that:

$P_{1}V_{1}=P_{2}V_{2}$

Where,

P is the pressure of the gas.

V is the volume of the gas.

Then, the given information is:

$V_{1}=125ml=0.125L\\P_{1}=1atm\\V_{2}=75ml=0.075L$

Remember, 1 L is equal to 1000 mL.

So,

$125mL*\frac{1L}{1000mL}=\frac{125mL*1L}{1000mL}=0.125L\\\\75mL*\frac{1L}{1000mL}=\frac{75mL*1L}{1000mL}=0.075L$

So, calculating the new volume, we have:

$P_{1}V_{1}=P_{2}V_{2}\\\\1atm*0.125L=P_{2}*0.075L\\\\P_{2}=\frac{1atm*0.125L}{0.075l}=1.67atm$

Hence, the new pressure is 1.67 atm.

Have a nice day!

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Ostrovityanka [42]

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