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Mumz [18]
3 years ago
12

If there are 40 mol of NBr3 and 48 mol of NaOH , what is the excess reactant ?

Chemistry
2 answers:
tekilochka [14]3 years ago
5 0
2NBr₃ + 3NaOH = N₂ + 3HOBr + 3NaBr
40 mol    48 mol

NBr₃:NaOH = 2:3

40:48 = 2:2.4 = 2.5:3

NBr₃ is the excess reactant
Paul [167]3 years ago
3 0

Answer:

NBr3

Explanation:

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