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finlep [7]
3 years ago
14

What is the percent by mass of oxygen in Ca(OH)2 ?

Chemistry
1 answer:
Leya [2.2K]3 years ago
7 0

Answer:

The answer to your question is Percent by mass = 43.2

Explanation:

Data

Ca(OH)₂

Percent by mass of Oxygen = ?

Process

1.- Calculate the molecular mass of Ca(OH)₂

    Ca(OH)₂ = (40 x 1) + (16 x 2) + (2 x 1)

                   = 40 + 32 + 2

                   = 74 g

2.- Calculate the mass of Oxygen = (16 x 2)

                                                        = 32 g

3.- Calculate the percent by mass

      Percent by mass = (mass of oxygen/mass of Ca(OH)₂) x 100

      Percent by mass = (32/74) x 100

      Percent by mass = 43.2

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a) What substances are present in an aqueous buffer composed of HC2H3O2 and C2H3O2 - ?b) What happens when LiOH is added to a bu
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Answer:

a) HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻

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Explanation:

a) In a HC₂H₃O₂/C₂H₃O₂⁻ buffer system, the following reactions take place:

HC₂H₃O₂ + H₂O ⇄ C₂H₃O₂⁻ + H₃O⁺

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b) When LiOH is added to the buffer system, it is partially neutralized according to the following equation.

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3 years ago
Compare the volume of 14.1 g of helium to 14.1 g of argon gas (under identical conditions).
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The Volumes can be calculated from Masses by using following Formula,

                                        Density  =  Mass / Volume
Solving for Volume,
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Mass of Both Gases  =  14.1 g

Density of Argon at S.T.P  =  1.784 g/L

Density of Helium at S.T.P  =  0.179 g/L

For Argon:
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                                        Volume  =  7.90 L

For Helium:
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                                        Volume  =  78.77 L
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