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3 years ago

10

Why neon is in the same group as helium?

1 answer:

guajiro [1.7K]3 years ago

5 0

Neon and helium are both gases that fall under the Noble Gases section in the periodic table of elements.

Hope this helped to answer your question. :D

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In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t

Mamont248 [21]

Answer:

a) $h_{max}=14536.16 m$

b) $h = 15687.9 m$

c) $PD=7.62\%$ The estimate is low.

Explanation:

a) Using the energy conservation we have:

$E_{initial}=E_{final}$

we have kinetic energy intially and gravitational potential energy at the maximum height.

$\frac{1}{2}mv^{2}=mgh_{max}$

$h_{max}=\frac{v^{2}}{2g}$

$h_{max}=\frac{43^{2}}{2*0.0636}$

$h_{max}=14536.16 m$

b) We can use the equation of the gravitational force

$F=G\frac{mM}{R^{2}}$ (1)

We have that:

$F = ma$ (2)

at the surface G will be:

$G=\frac{gR^{2}}{M}$

Now the equation of an object at a distance x from the surface.

is:

$F=\frac{mgR^{2}}{(R+x)^{2}}$

$m\frac{dv}{dt}=\frac{mgR^{2}}{(R+x)^{2}}$

Using that dv/dt is vdx/dt and integrating in both sides we have:

$v_{0}=\sqrt{\frac{2gRh}{R+h}}$

$h=\frac{v_{0}^{2}R}{2gR-v_{0}^{2}}$

$h=15687.9$

c) The difference is:

So the percent difference will be:

$PD=|\frac{14536.16-15687.9}{(14536.16+15687.9)/2}*100%$

$PD=7.62\%$

The estimate is low.

I hope it helps you!

7 0

3 years ago

sage has a walking speed of 300 feet per minute on the way to gate 14c at the airport sage has the option of using a moving side

nalin [4]

Answer:

2 min 40 s.

Explanation:

Distance = 800 ft

Speed (walking speed) = 300 ft/min

Speed = distance/time

Time, t = 800/300

= 8/3

= 2 min 40 s.

4 0

3 years ago

How many neutrons are present in an atom of iron-54? A) 26 B)28 C)30 D) 54

aleksklad [387]

Answer:

b

Explanation:

4 0

4 years ago

Read 2 more answers

In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested travelin

alexandr402 [8]

Answer:

a) $v=0.999124c$

b) $E=7.566*10^{22}$

c) $E_a=760 times\ larger$

Explanation:

From the question we are told that

Distance to Betelgeuse $d_b=430ly$

Mass of Rocket $M_r=20000$

Total Time in years traveled $T_d=36years$

Total energy used by the United States in the year 2000 $E_{2000}=1.0*10^20$

Generally the equation of speed of rocket v mathematically given by

$v=\frac{2d}{\triangle t}$

$v=860ly/ \triangle t$

where

$\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}$

$\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}$

$\triangle t=\sqrt{(860)^2+(36)^2}$

$\triangle t=860.7532$

Therefore

$v=\frac{860ly}{ 860.7532}$

$v=0.999124c$

b)

Generally the equation of the energy E required to attain prior speed mathematically given by

$E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2$

$E=7.566*10^{22}$

c)Generally the equation of the energy $E_a$ required to accelerate the rocket mathematically given by

$E_a=\frac{E}{E_{2000}}$

$E_a=\frac{7.566*10^{22}}{1.0*10^{20}}$

$E_a=760 times\ larger$

8 0

4 years ago

A golfer takes three putts to get the ball into the hole. The first putt displaces the ball 3.32 m north, the second 1.57 m sout

bixtya [17]

Answer:

The answer to the question is

The magnitude of the displacement needed to get the ball into the hole in just one putt is 1.746m in the direction of 23.41° north east

Explanation:

With trigonometric relation and the attached diagram we have

From the diagram the location of the hole is 3.32m- (1.57 cos45 +0.78co45)m North and

1.57sin 45 – 0.78 sin 45 meters west

1.658m north and

0.55m east

Thus the direction of the hole is 26.41 degrees

North east

The magbitude of the displacement is displacement is gotten from the relation diplacement of x and y =√(x²+y²)

$\sqrt{1.658^{2} +0.55^{2} } = 1.746 m$ ∠26.41°

3 0

3 years ago