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2 years ago

A. 1720 kJ B. 125.6 kJ C. 3440 kJ D. 4730 kJ

Chemistry

1 answer:

Feliz [49]2 years ago

7 0

Answer:

Q = 3440Kj

Explanation:

Given data:

Mass of gold = 2kg

Latent heat of vaporization = 1720 Kj/Kg

Energy required to vaporize 2kg gold = ?

Solution:

Equation

Q= mLvap

It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg

by putting values,

Q= 2kg × 1720 Kj/Kg

Q = 3440Kj

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