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4 years ago

When force is applied to an object, what happens

Physics

2 answers:

Nikitich [7]4 years ago

8 0

Answer:

The force on he object can cause an object to move or speed up. It can also make it stop or change direction.

Explanation:

Airida [17]4 years ago

3 0

The force on the object can cause an object to move or speed up, it can also make it stop or change direction

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Anyone know what type of circuit this is?

Oksana_A [137]

Answer:

Explanation:

BECAUSE ITS GOING ON AND ON IF ITS NOT CORRECT I WILL VOTE YOU BRAINLEST ON MY QUESTION

3 0

3 years ago

Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?

Hitman42 [59]

The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:

$h = \frac{v^{2}}{2g}$

<h3>What are perfectly elastic collision?</h3>

Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.

In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.

Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.

Since some of the Kinetic energy is converted to potential energy of the body;

$\frac{mv^{2}}{2} = mgh$

$h = \frac{v^{2}}{2g}$

Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.

Learn more about elastic collisions at: brainly.com/question/7694106

7 0

3 years ago

Mary and her younger brother Alex decide to ride the carousel at the State Fair. Mary sits on one of the horses in the outer sec

Alex

Answer:

ωM = 1.7 rad/s

vM = 3.4 m/s

ωA = 1.7 rad/s

vA = 1.7 m/s

Explanation:

Calculation of the angular speed (ω)

We use the following formula for circular motion:

ω = θ / t Formula (1)

Where:

ω: angular speed (rad/s)

θ:angle that the particle travels (rad)

t: time interval (s)

Equivalence

1 revolution = 2π rad

Data

θ= 1 revolution = 2π rad

t = 3.7 s

We replace data in the formula (1):

ω = (2π rad) / (3.7s )= 1.7 rad/s

Because the angular speed depends only on the number of turns in a time interval then Mary's angular speed (ωM) is equal to Alex's angular speed (ωA).

ωM = ωA = 1.7 rad/s

Calculation of the tangential speed (v)

We use the following formula for circular motion:

v = ω*r Formula (2)

Where:

v : tangential speed (m/s)

ω: angular speed ( rad/s)

r : radius of the circular path (m)

Data

ωM = ωM = ω= 1.7 rad/s

rM = 2m : Mary's circular path radius

rA = 1m : Alex's circular path radius

We apply the formula (2) to calculate v:

vM = ω* rM = (1.7) (2) = 3.4 m/s

vA = ω* rA = (1.7) (1) = 1.7 m/s

7 0

4 years ago

PLEASE HELP MEEEE <br>marking brainliest

aniked [119]

Answer:

Option C

Explanation:

Centripetal acceleration formula regarding velocity and radius is,

$a_c=\frac{v^2}{r}$

now we know the centripetal acceleration is 9 and the radius is 16 so we plug these values into our formula,

$a_c=\frac{v^2}{r}\\\\9=\frac{v^2}{16} \\\\144=v^2\\\\\sqrt{144}=v \\\\v=12\ m/s$

so velocity is 12 m/s

Now for the angular velocity, the formula of centripetal acceleration regarding angular velocity and radius is,

$a_c=rw^2$

we know the centripetal acceleration is 9 and the radius is 16 so plug these values into the formula,

$a_c=rw^2\\\\9=16w^2\\\\0.5625=w^2\\\\\sqrt{0.5625}=w \\\\0.75\ rad/s=w\\$

so angular velocity is 0.75 rad/s

8 0

3 years ago

g Light that is incident upon the eye is refracted several times before it reaches the retina. As light passes through the eye,

sertanlavr [38]

Answer

Explanation

:giác mạc

7 0

3 years ago