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Ratling [72]
3 years ago
13

An ice skater with a mass of 52.5 kg is gliding across a smooth lake with a speed of 2.25 m/s when she hits a spot of ice covere

d with snow. After a time of 7.55 s she has slowed to a stop. Using your knowledge of momentum, determine the magnitude of the average force of friction acting on the ice skater while she slows to a stop.
Physics
1 answer:
lidiya [134]3 years ago
8 0

Answer:

The magnitude of the average force of friction acting on the ice skater while she slows to a stop is 15.65 N

Explanation:

Given;

mass of the ice skater, m = 52.5 kg

speed of the ice skater, u = 2.25 m/s

time for her gliding, t = 7.55 s

To determine the magnitude of the average force of friction acting on the ice skater while she slows to a stop, we apply Newton's second law of motion;

F = ma

But, a = \frac{v-u}{t}

F =m (\frac{v-u}{t})

where;

F is average force of friction acting on the ice skater

v is the final speed speed of the ice skater = 0

u is the initial speed of the ice skater

t is time

F = m(\frac{v-u}{t} )\\\\F = 52.5(\frac{0-2.25}{7.55})\\\\F = -15.65 \ N

Thus, the magnitude of the average force of friction acting on the ice skater while she slows to a stop is 15.65 N

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timurjin [86]

Answer:

i hope it will be useful for you

Explanation:

F=5.6×10^-10N

R=93cm=0.93m

let take m1 and m2 =m²

according to newton's law of universal gravitation

F=m1m2/r²

F=m²/r²

now we have to find masses

F×r²=m²

5.6×10^10N×0.93m=m²

5.208×10^-9=m²

taking square root on b.s

√5.208×10^-9=√m²

so the two masses are m1=7.2×10^-5

and m2=7.2×10^-5

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4 years ago
If the force is 4 newtons between two charged spheres separated by 3 centimeters, calculate the force between the same spheres s
il63 [147K]

Answer:

1 Newton

Explanation:

F=9*10^9*q0q1/r^2]]

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4=9*10^9*(q0q1)/9

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q0q1=4/10^9

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To calculate the force between the forces at a distance of 6 cm

F=9*10^9*(q0q1)/ r^2

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So you raise the voltage and the resistance stays the same, the current will increase. That's why it will burn out sooner.

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The equation is a direct variation. If the voltage goes up the current goes up. If the voltage goes down, the current goes down providing that the resistance stays the same in both cases.

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Answer:slightly broken

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