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Novosadov [1.4K]
3 years ago
11

A thin spherical glass shell in air is filled with an unknown liquid. A horizontal parallel light beam is incident on the shell

and it is observed that the light is brought to focus on the surface of the shell directly opposite of the incoming beam. What is the refractive index of the liquid?
ie. the answer is 2- I just don't know how they got there
Physics
1 answer:
sammy [17]3 years ago
8 0
I have the exact same question, any chance you figured it out since you posted this?
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If a 50-kg Person is running at a rate of 2m/s, the person's momentum is _____ kg• m/s.
sergiy2304 [10]

Answer:

100

Explanation:

Use equation p=mv

p=(50kg)(2m/s)= 100

8 0
3 years ago
You are driving your 1700 kg car at 21 m/s down a hill with a 5.0∘ slope when a deer suddenly jumps out onto the roadway. You sl
podryga [215]

Answer:

d = 27.7 m

Explanation:

Here the car is driving on the inclined plane

So here we can say that work done by the gravity and work done by friction is equal to change in kinetic energy of the system

So here we can write it as

mgsin\theta \times d - F_f \times d = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

now we have

m = 1700 kg

v_f = 0

v_i = 21 m/s

F_f = 1.5 \times 10^4 N

(1700)(9.81)sin5 (d) - (1.5\times 10^4)d = 0 - \frac{1}{2}(1700)(21^2)

1453.5 d - (1.5\times 10^4)d = -374850

d = 27.7 m

6 0
3 years ago
A child of mass 40.0 kg is in a roller coaster car that travels in a loop of radius 7.00 m. at point a the speed of the car is 1
pav-90 [236]
I attached the missing picture.
The force of seat acting on the child is a reaction the force of child pressing down on the seat. This is the third Newton's law. The force of a child pressing down the seat and the force of the seat pushing up on the child are the same.
There two forces acting on the child. The first one is the gravitational force and the second one is centrifugal force. In this example, the force of gravity is always pulling down, but centrifugal force always acts away from the center of circular motion.
Part A
For point A we have:
F_a=F_cf-F_g
In this case, the forces are aligned, centrifugal is pointing up and gravitational is pulling down.
F_a=m\frac{v^2}{r}-mg=179 $N
Part B
At the point, B situation is a bit more complicated. In this case force of gravity and centrifugal force are not aligned. We have to look at y components of this forces, y-axis, in this case, is just pointing upward.
F=F_{cf}\cos(30)-mg=m\frac{v^2}{r}\cos(30)-mg=153.2$N
Part C
The child will stay in place at point A when centrifugal force and force of gravity are in balance:
F_g=F_{cf}\\
mg=m\frac{v^2}{r}\\
gr=v^2\\
v=\sqrt{gr}=8.29\frac{m}{s}

6 0
3 years ago
The primary purpose of describing planetary orbits in terms of epicycles and deferents was to account for the
dexar [7]
Retrograde. Planets seem to move forward and then backward sometimes. This is really because we pass them as we move in our orbit but astronomers wanted to try to describe the solar system with earth at the center so elaborate models were employed.
3 0
3 years ago
Calculate the speed of a car that traveled 200 kilometers in 3 hours.
nignag [31]

Answer:

The units (km/h) tell you how to do this! 200km/3h = 66.66666666…. BUT technically you only have ONE significant digit: 3 so 66.666… rounded to ONE digit is 70km/h but that is probably not important in this intro class so V = 66.67 or 67 km/h

8 0
3 years ago
Read 2 more answers
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