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Gala2k [10]
3 years ago
7

Question 2 of 10 >

Chemistry
1 answer:
KIM [24]3 years ago
7 0

Answer:

Moles of  H₂ left = 0.051 mol

Moles of ammonia formed = 0.34 mol

Explanation:

Given data:

Moles of N₂ = 0.170 mol

Moles of H₂ = 0.561 mol

Moles of ammonia formed = ?

Moles of H₂ left = ?

Solution:

Balance chemical equation:

N₂ + 3H₂       →     2NH₃

Now we will compare the moles of ammonia with nitrogen because nitrogen is limiting reactant and limit the yield of ammonia.

                  N₂          :           NH₃

                     1           :              2

                   0.170     :            2×0.170 = 0.34 mol

Moles of ammonia formed = 0.34 mol

Moles of H₂ reacted:

                   N₂           :            H₂

                    1             :             3

                  0.170       :            3/1×0.170 = 0.51 mol

0.51 moles of hydrogen react with 0.170 moles of nitrogen.

Moles of H₂ left:

Moles of H₂ left = Total - moles reacted

Moles of  H₂ left = 0.561 mol - 0.51 mol

Moles of  H₂ left = 0.051 mol

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Assuming temperature to be kept constant.

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PV = P'V' \\120\textrm{ KPa}\times 10\textrm{ m}^{3} = \textrm{P'}\times 3\textrm{ m}^{3} \\\textrm{P'} = 400\textrm{ KPa}

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2.  The trailing or ending zeroes are significant only in case of a decimal number otherwise they are ignored. However starting zeroes of such a number are not significant.

Now observing above rules, lets determine the location of the last significant place value of each given example. I am determining the location by turning the last significant place to bold.

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