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3 years ago

A box, compressing a spring by 4 m, is loaded and ready. Moments later the 8.0 kg box has been launched with

Physics

1 answer:

Mrac [35]3 years ago

3 0

Answer:

50 N/m

Explanation:

Elastic energy = kinetic energy

EE = KE

½ kx² = ½ mv²

½ k (4 m)² = ½ (8.0 kg) (10.0 m/s)²

k = 50 N/m

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What two roles do forensic engineers play?

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The 2 roles of forensic engineers is the detective role and then the engineering role.

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3 years ago

A paper filled capacitor is charged to a potential difference of 2.1 V and then disconnected from the charging circuit. The diel

Goryan [66]

Answer:

Part a)

$V' = 7.77 Volts$

Part b)

$k' = 6.27$

Explanation:

As we know that capacitor plate is connected across 2.1 V and after charging it is disconnected from the battery

So here we can say that charge on the plates will remain conserved

So we will have

$Q = kC(2.1)$

now dielectric is removed between the plates of capacitor

so new potential difference between the plates

$V' = \frac{Q}{C'}$

$V' = \frac{kC(2.1)}{C}$

$V' = 3.7 \times 2.1$

$V' = 7.77 Volts$

Part b)

Now the capacitor plates are again isolated and unknown dielectric is inserted between the plates

So again charge is same so potential difference is given as

$V" = \frac{Q}{k'C}$

$0.59 V = \frac{kCV}{k'C}$

$0.59 = \frac{3.7}{k'}$

$k' = 6.27$

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3 years ago

What is released when an excited electron returns to a lower energy state?

Marysya12 [62]

Answer:

A proton

Explanation:

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3 years ago

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True or false mechanical waves need a medium through which to transport energy

a_sh-v [17]

Answer:True

Explanation: The mechanical waves need a medium through which to transport energy because the perturbation travels inside of the medium so it needs molecules that connect elastically the displacement of the wave. For example the sound mainly uses the air molecules to transport the energy also the sound can be traveled in solid materials like metal rods.

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3 years ago

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A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.

MakcuM [25]

Answer:

b. 9.5°C

Explanation:

$m_i$ = Mass of ice = 50 g

$T_i$ = Initial temperature of water and Aluminum = 30°C

$L_f$ = Latent heat of fusion = $3.33\times 10^5\ J/kg^{\circ}C$

$m_w$ = Mass of water = 200 g

$c_w$ = Specific heat of water = 4186 J/kg⋅°C

$m_{Al}$ = Mass of Aluminum = 80 g

$c_{Al}$ = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

$m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C$

The final equilibrium temperature is 9.50022°C

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3 years ago