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gavmur [86]
3 years ago
8

Which of the following is a balanced chemical equation?

Chemistry
1 answer:
Gekata [30.6K]3 years ago
8 0
1. Not the first option because there are too many Oxygen molcecules on the right. ( 2O:  3O)

2. Not the second option because, again the oxygen's are not balanced. (6O:8O)

3.Correct! this is a balanced equation as there are equal amounts of all the molecules on each side of the reaction.

4. Not the fourth one because the Magnesium(Mg) are not balanced. (2Mg:1Mg)

Any Questions?

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A horse was 6,200 meters north of a barn. For 22.5 minutes, the horse ran toward the barn at 152 meters per minute. In that time
lutik1710 [3]

3420‬m

Explanation:

Given parameters:

Length of path = 6200m

time taken for the horse to run = 22.5min

speed = 152meters/minute

Unknown:

Distance run by the horse = ?

Solution:

Speed is the rate of change of distance with time.

   Speed       =    \frac{distance}{time}

    Distance = speed x time

 

     Distance = 152 x 22.5 = 3420‬m

learn more:

Speed          brainly.com/question/5424148

#learnwithBrainly

6 0
3 years ago
A man carrying a torch walks though a jungle on a very dark night. Suddenly, he sees two eyes looking down from a tree that seem
Brut [27]
D) The eyes in the tree are reflecting light from the torch into the man's eyes.
5 0
3 years ago
Using the table below, what is the change in enthalpy for the following reaction? 3CO (g) + 2Fe2O3 (s) Imported Asset Fe(s) + 3C
zhuklara [117]

To solve this problem, we should recall that the change in enthalpy is calculated by subtracting the total enthalpy of the reactants from the total enthalpy of the products:

ΔH = Total H of products – Total H of reactants

You did not insert the table in this problem, therefore I will find other sources to find for the enthalpies of each compound.

ΔHf CO2 (g) = -393.5 kJ/mol

ΔHf CO (g) = -110.5 kJ/mol

ΔHf Fe2O3 (s) = -822.1 kJ/mol

ΔHf Fe(s) = 0.0 kJ/mol

Since the given enthalpies are still in kJ/mol, we have to multiply that with the number of moles in the formula. Therefore solving for ΔH:

ΔH = [<span>3 mol </span><span>( − </span><span>393.5 </span>kJ/mol<span>) + 1 mol (</span>0.0 kJ/mol)<span>] − [</span><span>3 mol </span><span>( − </span><span>110.5 </span>kJ/mol<span>) + </span><span>2 mol </span><span>( − </span><span>822.1 </span>kJ/mol<span>)]</span>

ΔH = <span>795.2 kJ</span>

3 0
2 years ago
Is the cyanide ion a strong or weak base?
11111nata11111 [884]
It's a weak base bacause H C N is weak
4 0
2 years ago
Please help with this
dlinn [17]

Answer:

A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10 L to 15 L. The final pressure is 0.67 atm.

Step by Step Explanation?

Boyle's law states that in constant temperature the variation volume of gas is inversely proportional to the applied pressure.

The formula is,

P₁ x V₁ = P₂ × V₂

Where,

P₁ is initial pressure = 1 atm

P2 is final pressure = ? (Not Known)

V₁ is initial volume = 10 L

V₂ is final volume = 15 L

Now put the values in the formula,

\begin{gathered}\rm 1\times 10 = P_2\times 15\\\\\rm P_2 = \frac{10}{15\\} \\\\\rm P_2 = 0.67\end{gathered]

Therefore, the answer is 0.67 atm.

5 0
2 years ago
Read 2 more answers
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