Answer:
Ec = 6220.56 kcal
Explanation:
In order to calculate the amount of Calories needed by the climber, you first have to calculate the work done by the climber against the gravitational force.
You use the following formula:
(1)
Wc: work done by the climber
g: gravitational constant = 9.8 m/s^2
M: mass of the climber = 78.4 kg
h: height reached by the climber = 5.42km = 5420 m
You replace in the equation (1):
(2)
Next, you use the fact that only 16.0% of the chemical energy is convert to mechanical energy. The energy calculated in the equation (2) is equivalent to the mechanical energy of the climber. Then, you have the following relation for the Calories needed:
Ec: Calories
You solve for Ec and convert the result to Cal:
The amount of Calories needed by the climber was 6220.56 kcal
Answer:
Assuming that the length of the magnet is much smaller than the separation between it and the charge. As a result of magnetic interaction (i.e., ignore pure Coulomb forces) between the charge and the bar magnet, the magnet will not experience any torque at all - option A
Explanation:
Assuming that the length of the magnet is much smaller than the separation between it and the charge. As a result of magnetic interaction (i.e., ignore pure Coulomb forces) between the charge and the bar magnet, the magnet will not experience any torque at all; the reason being that: no magnetic field is being produced by a charge that is static. Only a moving charge can produce a magnetic effect. And the magnet can not have any torque due to its own magnetic lines of force.
Answer:
Number of Significant Figures: 2
The Significant Figures are 3 6
Explanation:
= 3.60 × 102
(scientific notation)
= 3.60e2
(scientific e notation)
= 360 × 100
(engineering notation)
(one)
= 360
(real number)
Answer:
The answer is 18 N.
Explanation:
A force can be divided into components x and y components. The component along the x-axis is called the horizontal component and along the y-axis is called the vertical component. In this case, as the force is in a horizontal direction and is also known as x-component of force. The x- component of force is
Fx = Fcosθ
Fx = 22(cos 35°)
Fx = 22 x 0.819
Fx = 18 N
Child's horizontal pull forces are equal to that of frictional resistance force on the wagon.
Answer:132.0285
Explanation: Hope this helps!
