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eimsori [14]
2 years ago
8

How has the theory of the Universe changed over time?

Physics
1 answer:
vlabodo [156]2 years ago
6 0
Although the expansion of the universe gradually slowed down as the matter in the universe pulled on itself via gravity, about 5 or 6 billion years after the Big Bang, according to NASA, a mysterious force now called dark energy began speeding up the expansion of the universe again, a phenomenon that continues today.
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Erica (38 kgkg ) and Danny (46 kgkg ) are bouncing on a trampoline. Just as Erica reaches the high point of her bounce, Danny is
salantis [7]

Answer:

The speed with which just after he grabs her is 2.68 m/s.

Explanation:

Given that,

Mass of Erica, m = 38 m/s

Mass of Danny, m' = 46 kg

Erica reaches the high point of her bounce, Danny is moving upward past her at 4.9 m/s. At this moment, the initial speed of Erica will be 0. The momentum will remain conserved. Using the conservation of linear momentum as :

mu+m'u'=(m+m')V\\\\0+46\times 4.9=(38+46)V\\\\V=\dfrac{225.4}{84}\\\\V=2.68\ m/s

So, the speed with which just after he grabs her is 2.68 m/s. Hence, this is the required solution.

6 0
3 years ago
What statement is best supported by the information in the chart?
Pani-rosa [81]

Answer:

Object 1

Explanation:

6 0
3 years ago
PLSS HELP NOWW!!!!!!(01.01 LC) Which is an example of the force of attraction between two objects that have mass? (2 points) a M
Lyrx [107]

Answer:

pretty sure it is gravity

6 0
3 years ago
A motorist, traveling east on an open highway, sets his cruise control at 90.0 km/h. How far will he travel in 0.75 hours?
dimaraw [331]

Answer:

<h2>The answer is 67.5 km</h2>

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

distance = velocity × time

From the question we have

distance = 90 × 0.75

We have the final answer as

<h3>67.5 km</h3>

Hope this helps you

3 0
2 years ago
Read 2 more answers
An object of 4 cm length is placed at a distance of 18 cm in front of a convex mirror of radius of curvature 30 cm. Find the pos
erica [24]

Answer:

The position is 8.18cm from the mirror.

Nature is b=virtual

Size is 1.82cm

Explanation:

Note that for a convex mirror, the image distance and the focal length are negative;

Given

Object height H0 = 4cm

object distance u = 18cm

Radius of curvature R = 30cm

Since f = R/2

f = 30/2

f = -15cm

Recall that:

\frac{1}{f} =\frac{1}{u}+ \frac{1}{v}\\\frac{1}{-15}=\frac{1}{18}+\frac{1}{v}    \\\frac{1}{v} =\frac{1}{-15} -\frac{1}{18}\\ \frac{1}{v} = \frac{-18-15}{270}\\\frac{1}{v} = \frac{-33}{270}\\v=\frac{-270}{33}\\v=-8.18cm

Since the image distance is negative, this shows that the image is a virtual image.

To get the size:

\frac{H_1}{H_0}=\frac{v}{u}\\\frac{H_1}{4}=\frac{8.18}{18}\\18H_i=32.72\\H_i=\frac{32.72}{18}\\H_i= 1.82cm

3 0
3 years ago
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