The solubility product of a substance us calculated by the product of the concentration of the dissociated ions in the solution raise to the stoichiometric coefficient of the ions. Therefore, we need the dissociation reaction. For this, it will have the reaction:
PbI2 = Pb^2+ + 2I-
We solve as follows:
Ksp = [Pb2+][I-]^2 = <span>1.4 x 10-8
</span><span>1.4 x 10-8 = x(2x)^2
</span><span>1.4 x 10-8 = 4x^3
x = 1.5x10^-3 M
The molar solubility would be </span>1.5x10^-3 M.
Answer: 77.4 mL
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is:
where,
= initial pressure of dry gas = (760 - 17.5) mmHg= 742.5 mm Hg
= final pressure of dry gas at STP = 760 mm Hg
= initial volume of dry gas = 85.0 mL
= final volume of dry gas at STP = ?
= initial temperature of dry gas =
= final temperature of dry gas at STP =
Now put all the given values in the above equation, we get the final volume of wet gas at STP
Volume of dry gas at STP is 77.4 mL.
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