All categories

3 years ago

Name means near thyroid

Physics

1 answer:

fredd [130]3 years ago

7 0

Answer:

parathyroid hormone

Explanation:

You might be interested in

An important consideration in materials physics is the number of defects that are unavoidable due to statistical considerations.

goblinko [34]

Answer:

Explanation:

find attached the solution

8 0

3 years ago

How does Sonar work?i will mark brainliest pls help

Fittoniya [83]

I don't like the wording of any of the choices on the list.

SONAR generates a short pulse of sound, like a 'peep' or a 'ping',
focused in one direction. If there's a solid object in that direction,
then some of the sound that hits it gets reflected back, toward the
source. The source listens to hear if any of the sound that it sent
out returns to it. If it hears its own 'ping' come back, it measures
the time it took for the sound to go out and come back. That tells
the SONAR equipment that there IS a solid object in that direction,
and also HOW FAR away it is.

RADAR works exactly the same way, except RADAR uses radio waves.

5 0

3 years ago

What is the mass of a person running at 2.5 m/s with momentum of<br> 200 kg m/S

kondor19780726 [428]

Answer:

m = 80 kg

Explanation:

p = m × v

200 = m × 2.5

2.5m = 200

m = 200/2.5

m = 80 kg

5 0

3 years ago

What 3 types of metals have magnetic properties

satela [25.4K]

Ferromagnetic, paramagnetic, and diamagnetic

6 0

3 years ago

Read 2 more answers

If I wanted to generate a maximum emf of 20 V, what angular velocity (radians/sec, aka Hz) would be required given a circular co

sergij07 [2.7K]

Answer:

Angular velocity, $\omega=35.36\ rad/s$

Explanation:

It is given that,

Maximum emf generated in the coil, $\epsilon=20\ V$

Diameter of the coil, d = 40 cm

Radius of the coil, r = 20 cm = 0.2 m

Number of turns in the coil, N = 500

Magnetic field in the coil, $B=9\times 10^{-3}\ T$

The angle between the area vector and the magnet field vector varies from 0 to 2 π radians. The formula for the maximum emf generated in the coil is given by :

$\epsilon=NBA\omega$

$\omega=\dfrac{\epsilon}{NBA}$

$\omega=\dfrac{20\ V}{500\times 9\times 10^{-3}\ T\times \pi (0.2\ m)^2}$

$\omega=35.36\ rad/s$

So, the angular velocity of the circular coil is 35.36 rad/s. Hence, this is the required solution.

6 0

3 years ago