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Alex Ar [27]
4 years ago
5

Name means near thyroid

Physics
1 answer:
fredd [130]4 years ago
7 0

Answer:

parathyroid hormone

Explanation:

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The correct option is;

D. The kinetic energy decreases by 3·m₀·v₀²

Explanation:

The given parameters are;

The mass of object X = m₀

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The mass of object Y = 2·m₀

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By conservation of linear momentum, we have;

The total initial momentum = The total final momentum

Therefore, we have;

The total initial momentum = m₀·v₀ - 2·m₀·2·v₀ = The total final momentum

∴ The total final momentum = -3·m₀·v₀

The total mass of the two object after sticking together = 2·m₀ + m₀ = 3·m₀

Therefore, the velocity of the two objects after collision = (The total final momentum)/(Total mass) = -3·m₀·v₀/(3·m₀) = -v₀

The kinetic energy = 1/2 × Mass × (Velocity)²

Therefore, the kinetic energy after collision = 1/2 × (3·m₀) × v₀² = 3·m₀·v₀²/2

The kinetic energy before collision = 1/2 × m₀ × v₀² + 1/2 × (2·m₀) × (2·v₀)² = (1/2 + 4) × (m₀·v₀²)

∴ The kinetic energy before collision =  9·(m₀·v₀²)/2

The change in kinetic energy = The kinetic energy after collision - The kinetic energy before collision = 3·m₀·v₀²/2 - 9·(m₀·v₀²)/2 = -3·m₀·v₀²

Therefore, the kinetic energy decreases by 3·m₀·v₀².

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Consider a mass initially moving at 7.50 m/s. How does it take to move 3.5 km (Be sure to convert to meters) if it accelerates a
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The mass is moving by uniformly accelerated motion, with initial velocity v_i=7.50 m/s and acceleration a=0.55 m/s^2. Its position at time t is given by the following law:
x(t)=v_i t + \frac{1}{2}at^2
where we take the initial position x_i=0 since we are only interested in the distance traveled by the mass.

If we put x(t)=d=3.5 km=3500 m into the equation, the corresponding time t is the time it takes for the mass to travel this distance:
\frac{1}{2}at^2+v_it-d=0
4.9t^2+7.5t-3500 =0
And the two solutions for the equation are:
t=-25.5 s --> negative, we can discard it
t=24.0 s --> this is the solution to our problem
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A hockey puck is at rest on a flat surface. Then one end of the surface is lifted gradually, forming an inclined plane of increa
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