Answer:
0.39
Explanation:
distance from the center (r) = 32 cm = 0.32 m
speed of the coin (v) = 110 cm/s = 1.1 m/s
acceleration due to gravity (g) = 980 m/s^{2} = 9.8 m/s^{2}
find the coefficient of static friction (k) between the coin and the turn table
frictional force = kmg
before the table begins to move, the frictional force balances the centripetal force (
)
therefore
frictional force = centripetal force
kmg = ![\frac{mv^{2} }{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%5E%7B2%7D%20%7D%7Br%7D)
kg = ![\frac{v^{2} }{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%5E%7B2%7D%20%7D%7Br%7D)
k =
÷ g
k =
÷ 9.8 = 0.39
Answer:
50 kg
Explanation:
fnet=ma
600-200=m8
divide both side by 8 to make m the subject of the formula Thus m=50kg
The law of conservation of momentum<span> states that for two objects colliding in an isolated system, the total </span>momentum<span> before and after the collision is equal. Momentum should be conserved. Hope this answers the question. Have a nice day.</span>
Answer:
You now this question state why a person standing at point Y hears an echo
Answer:
q = 2.65 10⁻⁶ C
Explanation:
For this exercise we use Coulomb's law
F =
In this case they indicate that the load is of equal magnitude
q₁ = q₂ = q
the force is attractive because the signs of the charges are opposite
F =
q =
we calculate
q =
q =
Ra 7 10-12
q = 2.65 10⁻⁶ C