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ruslelena [56]
3 years ago
6

Density of water is 1000kg/meter cube. what will be the volume of 35000kg water ​

Physics
1 answer:
Lana71 [14]3 years ago
4 0

Answer:

i think 35 cubic meters of water

Explanation:

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Everyday activities do NOT produce significant muscle growth because:
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Driving along in your car, you take your foot off the gas, and your speedometer shows a reduction in speed. Describe an inertial
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Answer:

  v ’= v + v₀

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Explanation:

In an inertial reference frame the speed of the vehicle is given by the Galileo transformational

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where v 'is the speed with respect to the mobile system, which moves with constant speed, v is the speed with respect to the fixed system and vo is the speed of the mobile system.

The vehicle's speedometer measures the harvest of a fixed system on earth, in this system v decreases, for a system where v 'increases it has to be a system in which the mobile system moves in the negative direction of the x axis, whereby the transformation ratio is

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Over a period of operation, the useful work output of the fluorescent bulb was
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An object 1,000 km above earths surface would accelerate
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The acceleration which is gained by an object because of the gravitational force is called its acceleration due to gravity. Its SI unit is m/s2. Acceleration due to gravity is a vector, which means it has both a magnitude and a direction. The formula is ‘the change in velocity= gravity x time’ The acceleration due to gravity at the surface of Earth is represented as g. It has a standard value defined as 9.80665 m/s2.[1]

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A charge of Q is fixed in space. A second charge of q was first placed at a distance r1 away from Q. Then it was moved along a s
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Answer:

\Delta U = \frac{Qq}{4\pi\epsilon_0}(\frac{1}{r_2^2}-\frac{1}{r_1^2})

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U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}

Now, we will apply this formula to both cases:

U_1 = \frac{1}{4\pi\epsilon_0}\frac{Qq}{r_1^2}\\U_2 = \frac{1}{4\pi\epsilon_0}\frac{Qq}{r_2^2}

So, the change in the potential energy is

\Delta U = U_2 - U_1 = \frac{Qq}{4\pi\epsilon_0}(\frac{1}{r_2^2}-\frac{1}{r_1^2})

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