The DH for the solution process when solid sodium hydroxide dissolves in water is -44.4 kJ/mol. When a 13.9-g sample of NaOH dis
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CH₄ + 2O₂ → CO₂ + 2H₂O
From the equation, we know that methane and carbon dioxide have the same number of moles.
no. of moles of CO₂ produced = no. of moles of methane
= 4.5 × 10⁻³ ÷ (12 + 1×4)
= 2.8125 × 10⁻⁴
∴ mass of CO₂ = 2.8125 × 10⁻⁴ × (12 + 16×2)
= 12.375 × 10⁻³ g
<em>here is the structure given below ,,, you can easily understand the structure:</em>
