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timurjin [86]
3 years ago
9

What is the pH of a solution which is 0.600 M in dimethylamine ((CH3)2NH) and 0.400 M in dimethylamine hydrochloride ((CH3)2NH2C

l)? Kb for dimethylamine = 7.4x10-4.
Chemistry
1 answer:
Viefleur [7K]3 years ago
3 0

Answer:

pH = 11.05

Explanation:

It is possible to answer this question using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [A] / [HA⁺]

Where A in this case is weak base (dimethylamine) and conjugate acid (HA⁺) is dimethylamine hydrochloride.

As Ka= Kw / Kb = 1x10⁻¹⁴ / 7.4x10⁻⁴ = 1.35x10⁻¹¹ And pKa is -log Ka = <em>10.87 </em> pH of the solution is:

pH = 10.87 + log₁₀ [0.600] / [0.400]

<em>pH = 11.05</em>

<em></em>

I hope it helps!

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