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2 years ago

C3H8 + xO2 > 3CO2 + yH2O which value of x and y balance the equations

Chemistry

1 answer:

Gelneren [198K]2 years ago

8 0

Answer:

x = 5 and y =4

Explanation:

An alkane is a hydrocarbon of general molecular formula CnH2n+2. The general formula for balancing the combustion equation of any alkane is;

CnH2n+2 + 3n+1/2O2 ------> nCO2 + (n+1) H2O

Where n is the number of carbon atoms in the alkane.

In C3H8 , n=3 so;

C3H2(3)+2 + 3(3)+1/2O2 ------> 3CO2 + (3+1) H2O

Then;

C3H8 + 5O2 ------> 3CO2 + 4H2O

Therefore;

x = 5 and y =4

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3 years ago

Identify the combustion reaction. identify the combustion reaction. c(s) + o2(g) → co2(g) 2 h2(g) + o2(g) → 2 h2o(g) c3h8(g) + 5

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3 years ago

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vfiekz [6]

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3 years ago

A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach the

butalik [34]

Answer:

0.172 M

Explanation:

The reaction for the first titration is:

HCl + NaOH → NaCl + H₂O

First we calculate how many HCl moles reacted, using the given concentration and volume:

19.6 mL * 0.189 M = 3.704 mmol HCl

As one HCl mol reacts with one NaOH mol, there are 3.704 NaOH mmoles in 25.0 mL of solution. With that in mind we determine the NaOH solution concentration:

3.704 mmol / 25.0 mL = 0.148 M

As for the second titration:

H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

We determine how many NaOH moles reacted:

34.9 mL * 0.148 M = 5.165 mmol NaOH

Then we convert NaOH moles into H₃PO₄ moles, using the stoichiometric coefficients:

5.165 mmol NaOH * $\frac{1mmolH_3PO_4}{3mmolNaOH}$ = 1.722 mmol H₃PO₄

Finally we determine the H₃PO₄ solution concentration:

1.722 mmol / 10.0 mL = 0.172 M

5 0

3 years ago

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Fynjy0 [20]

Answer:

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Explanation:

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3 0

3 years ago